sinA - cosA +1 / sinA + cosA -1 = secA + tanA
Now secA = 1/cosA and tanA = sinA/cosA
So sinA - cosA +1 / sinA + cosA -1 = 1/cosA + sinA / cosA
From now on I'll write sinA = s and cosA = c :-
(s - c + 1 )/ (s + c - 1) = 1/c + s/c
(s - c + 1) / (s + c - 1) = (1 + s) / c
Cross multiply:-
s + c - 1 + s^2 + sc - s = sc - c^2 + c
s^2 + c + sc - 1 = sc - c^2 + c
s^2 - 1 + sc - sc + c - c = -c^2
s^2 - 1 = -c^2
-(1 - s^2) = - c^2
Now 1 - s^2 = c^2 so:-
- c^2 = - c^2
So the identity is proved
Answer:
The variance of the temperatures of the 10 day period must be at least zero.
Step-by-step explanation:
The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.
Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.
Since the variance is squared, it will always have values greater than zero.
Distance travelled must be equal to fuel conserved in travelling per litre
distance=9 1/2*25.2
=19/2*25.2
=239.4 miles
Answer:
y= 288
Step-by-step explanation:
Please see the attached picture for full solution.
