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Basile [38]
2 years ago
15

A circle with radius 3 centimeters is cut from a square piece of felt.The sides of the felt square are 8 centimeter long. How mu

ch felt is left over? use 3.14 for π. Show your work.
please try to answer this asap
Mathematics
1 answer:
Roman55 [17]2 years ago
3 0

3.14 x 3 =9.42

8 x 4 = 32

32-9.42= 22.58cm squared

I think this is correct, I’m not sure

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4⋅10 ​6 ​​ 4, dot, 10, start superscript, 6, end superscript is how many times as large as 1\cdot10^41⋅10 ​4 ​​ 1, dot, 10, star
lesya [120]

The given problem is very confusing since it was copy pasted directly from the source so the equations look scrambled and plus it was one words. After my own translation, I believe the given numbers are:

4 ⋅ 10^6

and

1 ⋅ 10^4

The symbol ⋅ means that the two numbers are multiplied while the symbol ^ means an exponent of. Now we are asked to find how much the 1st number is larger than the 2nd number. To solve this, we simply have to divide the bigger number by the smaller number. Since 4 ⋅ 10^6 has bigger exponent than 1 ⋅ 10^4 then it is the bigger number.

Ratio = 4 ⋅ 10^6 / 1 ⋅ 10^4

Ratio = 4 ⋅ 10^2 = 400

Therefore 4 ⋅ 10^6 is 400 times bigger than 1 ⋅ 10^4.

 

Answer:

<span>400 times</span>

6 0
3 years ago
What is the reminder? Help
Vanyuwa [196]

Answer:

6

Step-by-step explanations:

The remainder is what is left over after dividing whatever from d. So if you add one to d, then the remainder would increase from 5 to 6.

Hope this helps.

4 0
3 years ago
Simplify<br>2 1 <br>- + -<br>3 11​
Papessa [141]

Answer:

0.1515151515151515

Step-by-step explanation:

3 0
3 years ago
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Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
Yanka [14]

Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

\sigma^2 =\frac{1}{5}*[162]

\sigma^2 =32.4

Solving (c): The standard deviation

This is calculated as:

\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0
3 years ago
What is 8/90 in simplest form
STALIN [3.7K]
8/90 in simplest form is 4/45
3 0
3 years ago
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