The given problem is very confusing since it was copy
pasted directly from the source so the equations look scrambled and plus it was
one words. After my own translation, I believe the given numbers are:
4 ⋅ 10^6
and
1 ⋅ 10^4
The symbol ⋅ means
that the two numbers are multiplied while the symbol ^ means an exponent of.
Now we are asked to find how much the 1st number is larger than the
2nd number. To solve this, we simply have to divide the bigger
number by the smaller number. Since 4 ⋅ 10^6
has bigger exponent than 1 ⋅ 10^4
then it is the bigger number.
Ratio = 4 ⋅ 10^6 /
1 ⋅ 10^4
Ratio = 4 ⋅ 10^2 =
400
Therefore 4 ⋅ 10^6
is 400 times bigger than 1 ⋅ 10^4.
Answer:
<span>400 times</span>
Answer:
6
Step-by-step explanations:
The remainder is what is left over after dividing whatever from d. So if you add one to d, then the remainder would increase from 5 to 6.
Hope this helps.
Answer:
0.1515151515151515
Step-by-step explanation:
Answer:



The standard deviation will remain unchanged.
Step-by-step explanation:
Given

Solving (a): The range
This is calculated as:

Where:

So:


Solving (b): The variance
First, we calculate the mean




The variance is calculated as:

So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)

Solving (c): The standard deviation
This is calculated as:


--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
8/90 in simplest form is 4/45