5.5L= 5500ml
5500*1.06g/ml=5830g
5803g*0.035274oz/g=205.6oz
The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.
<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>
The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.
The equation of the reaction is given below:
![CuSO_4 + Fe \rightarrow FeSO_4 + Cu](https://tex.z-dn.net/?f=CuSO_4%20%2B%20Fe%20%5Crightarrow%20FeSO_4%20%2B%20Cu)
The mole ratio of both reactants and product is 1 : 1
molar mass of copper sulfate = 160 g
molar mass of Cu = 64
molar mass of iron = 56 g
- mole ratio of iron to copper = 1 : 1
moles of Cu in 1.5 g = 1.5/64 = 0.00234
mass of iron required = 0.00234 × 56 = 1.31 g of iron
Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.
Learn more about mole ratio at: brainly.com/question/19099163
Answer:
3.4 × 10^23 molecules
Explanation:
To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).
number of molecules = number of moles (mol) × 6.02 × 10^23?
Number of molecules = 0.565 × 6.02 × 10^23
3.4 × 10^23 molecules