Answer:
44.8 L
Explanation:
Ideal Gas Equation -
i.e.,
PV = nRT
where,
P = pressure
V = volume
n = moles
R = universal gas constant
T = temperature
Using the information given in the question, Volume of the gas can be calculated -
P = 101.3 kPa
V = ?
n = 2.00 moles
R = 8.31
T = 0 degree C = 273.15 K
Using the above data, and putting the data in the respective formula -
PV = nRT
101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K
V = 44.8 L
Hence, the volume of the given gas = 44.8 L
Answer:
Over hundreds of years
Explanation:
Just did the test and got it right
Given :
Number of moles of CHF₃ is 1.7 .
Solution :
We know, 1 mole of any complex contains 6.022 × 10²³ molecules.
Let, 1.7 moles of CHF₃ contains n numbers of molecules.
So, n = 1.7 × 6.022 × 10²³ molecules
n = 10.2374 × 10²³ molecules
n = 1.0237 × 10²³ molecules
Hence, this is the required solution.
Co= 59g
S=32g
59+32=91g/mol
The most basic level of organization that is involved in converting fuel or food into forms of energy, are found and compose living things. These are called cells.
