Select the correct answer. What happens as you decrease the temperature of a solution?

C como Se define una cuenca hidrogatica Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

sladkih [1.3K]

Answer:

Una cuenca es un área de tierra que drena todos los arroyos y la lluvia a una salida común, como la salida de un embalse, la boca de una bahía o cualquier punto a lo largo del canal de un arroyo.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0

3 years ago

Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1

Korvikt [17]

The molecular mass of Carvone is calculated as;

= 12 (C)₁₀ + 1.008 (H)₁₄ + 16 (O)

= 120 + 14.112 + 16

= 150.112

%age of Carbon;

= (120 ÷ 150.112) × 100

= 79.94 %

%age of Hydrogen;

= (14.112 ÷ 150.112) × 100

= 9.40 %

%age of Oxygen;

= (16 ÷ 150.112) × 100

= 10.65 %

7 0

3 years ago

When a 0.245-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.260-g sample

sveticcg [70]

Answer:

The heat of combustion per moles of caffeine is 4220 kJ/mol

Explanation:

Step 1: Data given

⇒ When benzoic acid sample of 0.245 grams is burned the temperature rise is 1.643 °C

⇒ When 0.260 gram of caffeine is burned, the temperature rise is 1.436 °C

⇒ Heat of combustion of benzoic acid = 26.38 kJ/g

Step 2: Calculate the heat released: for combustion of benzoic acid

0.245 g benzoic acid * 26.38 kJ/g = 6.4631 kJ

Step 3: Calculate the heat capacity of the calorimeter:

c = Q/ΔT

Q = 6.4631 kJ / 1.643°C = 3.934 kJ/ °C

Step 4: Calculate moles of a 0.260 g sample of caffeine:

Moles caffeine = Mass caffeine / Molar mass caffeine

0.260 grams/ 194.19 g/mol = 0.0013389 moles

Step 5: Calculate heat released: for combustion of caffeine

Q = c * ΔT

Q = 3.934 kJ/°C * 1.436 °C = 5.65 kJ

Step 6: Calculate the heat of combustion per mole of caffeine

5.65 kJ / 0.0013389 moles = 4219.9 kJ/mol ≈ 4220 kJ/mol

The heat of combustion per moles of caffeine is 4220 kJ/mol

4 0

3 years ago

Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at

kozerog [31]

Answer:

20 g/mol

Explanation:

We can use Graham’s Law of diffusion:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r = \frac{1 }{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

Squaring both sides, we get

$(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}$

Solve for M₂:

$M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}$

$M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}$

$= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}$

7 0

3 years ago

What part of the atom determines if it will combine or break apart from other substances?

anzhelika [568]

Answer:

The atom consist of three parts, proton, neutron and electrons. The electrons determine that i will combine or beak from other substances.

Explanation:

The atom consist of three parts which are following

proton
neutron
electron

The proton and neutron form nucleus of an atom. It is present at center of an atom. They have positive charges, while electrons remained outside the nucleus in particular energy levels or shell around the nucleus.

During combination or breaking of substances ,only arrangements of electrons take place. The valence shell electrons decide whether they have to combine or not, while nucleus remained unchanged during any reactions.

3 0

3 years ago