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SCORPION-xisa [38]

3 years ago

11

3. At a local restaurant, the health inspector visits every 7 days, and the fire inspector visits every 12 days.

1 answer:

suter [353]3 years ago

6 0

Health inspector:7,14,21,28
Fire inspector:12,24,36,48
They will both be there on day 84

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How bad is the heavy traffic? you could walk 15 miles in the same time it takes to travel 30 miles by car. if the cars rate is 4

Pepsi [2]

The answer is 454 because 10*30+4=454

3 0

4 years ago

Find the value of x of the given right triangle.

Firlakuza [10]

Answer:

In the right triangle, the side a= $4$ and the hypotenuse c= $7$ .

To find: the value of x

We have,

$a=6$ and $c=7$

Now,by the pythagorean theorem,

${a}^{2} + {b}^{2} = {c}^{2}$

Substitute the values,

${6}^{2} + {x}^{2} = {7}^{2}$

$36 + {x}^{2} = 49$

Subtract 36 from each sides,

${x}^{2} = 13$

Take square root from each sides,

$x = \sqrt{13}$

Hence, the value of x is $\sqrt{13}$ .

6 0

2 years ago

Can someone please help me ASAP

charle [14.2K]

Answer:

(4,12)

(-1,-3)

Step-by-step explanation:

x^2 - y = 4

y = 3x

Use substitution. Substitute 3x for y in the first equation

x^2 - (3x) = 4

x^2 -3x =4

Subtract 4 from each side

x^2 -3x -4 = 4-4

x^2 -3x-4 =0

Factor

(x-4) (x+1) =0

Using the zero product property

x-4 =0 x+1 =0

x=4 x=-1

Now to find y for each x solution

x=4

y =3x = 3(4) =12

(4,12)

x=-1

y =3x = 3(-1) =-3

(-1,-3)

4 0

4 years ago

An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

$W_s=2.66817984*2$

$W_s=5.33635968$

$W_s \approx5.3$

3 0

3 years ago

Bett you guys can help meif you do tho you don’t have corona ✌

blsea [12.9K]

Guess I have corona....................

7 0

3 years ago