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3 years ago

15

The two box and whisker plots below show the times in seconds for two teams in a 100m dash . What do the interquartile ranges te

ll you about the two teams

1 answer:

devlian [24]3 years ago

7 0

The first box plot shows the value of Q1 = 32 and Q3 = 37. Hence the Interquartile range = 37-32 = 5

The second box plot shows the value of Q1 = 29 and Q3 = 36, Hence the interquartile range = 36-29 = 7

Team B has bigger interquartile range than team A and it shows that the data spreads more than Team A's

It also shows that Team A's scores are more consistent

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Please help me I need help today thank you and please show work

scoundrel [369]

17) $x-8=11$

18) $9-x=5$

19) $x+6=7$

20) $x+(-4)=-18$

Step-by-step explanation:

17) The difference between a number and 8 is 11

Let number = x

then the equation will be:

$x-8=11$

Solving:

$x-8=11$

$x=11+8\\x=19$

18) Nine less than a number is five.

Let number = x

then the equation will be:

$9-x=5$

Solving:

$9-x=5\\-x=5-9\\-x=-4\\x=4$

19) Seven is equal to a number plus 6

Let number = x

then the equation will be:

$x+6=7$

Solving:

$x+6=7\\x=7-6\\x=1$

20) The sum of a number and -4 is -18

Let number = x

then the equation will be:

$x+(-4)=-18$

solving:

$x+(-4)=-18\\x-4=-18\\x=-18+4\\x=-14$

Keywords: Algebraic Expressions

Learn more about Algebraic Expressions at:

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3 years ago

A rectangular prism with length width and heighth has a volume of two

kobusy [5.1K]

Answer:

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2 years ago

Write the equation of the line that passes through (−1, 5) and has a slope of 3 in point-slope form. (2 points)

Sonbull [250]

-1 = 3(5) + b
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-16 = b

y = 3x -16
y - 5 = 3(x +1)

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Answer:

(4c-1)(y+3)

Step-by-step explanation:

4c(y+3) -(y+3)

=(4c-1)(y+3)

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3 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

<em>l</em> denotes length
<em>b</em> denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

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3 years ago