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galben [10]
3 years ago
15

The two box and whisker plots below show the times in seconds for two teams in a 100m dash . What do the interquartile ranges te

ll you about the two teams

Mathematics
1 answer:
devlian [24]3 years ago
7 0
The first box plot shows the value of Q1 = 32 and Q3 = 37. Hence the Interquartile range = 37-32 = 5

The second box plot shows the value of Q1 = 29 and Q3 = 36, Hence the interquartile range = 36-29 = 7

Team B has bigger interquartile range than team A and it shows that the data spreads more than Team A's

It also shows that Team A's scores are more consistent
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Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0
2 years ago
A cone has a radius of 5 cm and a height of 9 cm. What is the volume of the cone to the nearest whole number? Use 3.14 for pi.
Katyanochek1 [597]

Answer:

235or 236

Step-by-step explanation:

A cone has a radius of 5 cm

a height of 9 cm

Volume of cone =1/3πr^2h

=1/3×3.14×5×5×9

= 3.14×25×3

=3.14×75

=235.5

=235or 236 is the answer

8 0
2 years ago
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