On the internet, I found
Research topics
Artificial Intelligence
Computing and Mathematics
Cybersecurity
Data Science and Machine Learning
Embedded Systems and IoT
Process Management
Hope this helped :T
A method is written with the header 'num' yourMethod(string name, num code). The method's type is <u>'num'.</u>
In the context of programming. a header refers to supplemental data placed at the beginning of a block of data being transmitted or stored. In the context of the Java method, the header is where you tell the Java program what value type if any, the method will return (a string value, an int value, a double value, etc). As well as the return type, you require a name for your method, which is also placed in the header. You can pass values over to your methods in between a pair of round brackets.
You can learn more about method in Java at
brainly.com/question/28489761
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It takes places during surveying.
For example, let's say you want to review your own produced game application software, and found out whether it satisfy your consumer or not
Before you conduct the survey, you have to identify what aspect you want to find out from your consumers , such as : Does it have any bug ? Is it challenging enough ? is the graphic good enough ? etc
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
