The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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It will be 600 cubic meters because cubic meters and liters are equal same goes with cubic centimeters and milliliter
Answer:
Therefore the population will be maximum when x=30 inches.
Step-by-step explanation:
Given that, the mosquito population is a function of rainfall and can be approximated by the formula

where x is the number of inches of rainfall.

Differentiating with respect to x

Again differentiating with respect to x

Now we set N'(x)=0





Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.
Therefore the population will be maximum when x=30 inches.
Answer:
4+m=4m
Step-by-step explanation:
Because 4 plus m is 4m
Answer:
-2s
Step-by-step explanation:
2s+(-4s)
2s-4s
-2s
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