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svlad2 [7]
3 years ago
5

Find the product.

Mathematics
2 answers:
notsponge [240]3 years ago
8 0

Answer:

A) 4n²- 4

Step-by-step explanation:

use the FOIL method:

F = first, meaning multiply the 1st terms in each factor

O = outer, meaning multiply the 1st term in first factor and last term in second

I = inner, meaning multiply the 2nd term in first factor and 1st term in second

L = last, meaning multiply the last terms in each factor

F = 2n · 2n = 4n²

O = 2n(-2) = -4n

I = 2(2n) = 4n

L = 2(-2) = -4

you have 4n² - 4n + 4n - 4

this can be simplified by adding the two middle terms (which will zero out):

4n²- 4

Harrizon [31]3 years ago
5 0

(2n+2)(2n-2)\\\\=(2n)^2 -2^2 ~~~~~~;[a^2 -b^2 =(a-b)(a+b)]\\\\=4n^2 -4

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