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avanturin [10]
3 years ago
12

Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and th

ey are both dimes. He says the probability of that occurring is 1/4 because 2 of the 8 coins are dimes. Is he correct? Explain
Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

No. Choosing two dimes are dependent events. The probability of choosing the first dime is 1/4 and the probability of choosing the second dime is 1/7 . The probability that both coins are dimes is

Step-by-step explanation:

Crank3 years ago
4 0

Answer:

.

Step-by-step explanation:

The events are dependent.

The size of the original sample space is 8. It changes to 7 after the first dime is chosen.

The probability of picking the first dime is 2/8.

The probability of picking the second dime is 1/7

To find the probability of the compound event, multiply the probabilities.

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Graph the solution of the inequality –3(x + 1) ≤ 6 on the number line.
fomenos
First you solve the inequality. Add the variables that can be added together. That would be -3 + 1=2. Now the equation is 2 + x<6. After you change the 2 into a negative and put it under the 6 and subtract. that is 3. 3 is the number you put on the number line. When you fine and plot three you make a dot above it. You fill in the dot since the less then sign has a line beneath it. Then you draw a line from the dot to the end of the number line from the direction the sign is facing. It’s a less then sign, so you would draw the line to the left.
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Help I need answers now
Juli2301 [7.4K]

Answer:

<u>The Answer in Exact Form:</u>

-3/22

<u>In Decimal Form:</u>

-0.136

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Answer: { x | 5 < x ≤ 100 }  OR  { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

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Another acceptable way to write this is

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