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avanturin [10]
3 years ago
12

Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and th

ey are both dimes. He says the probability of that occurring is 1/4 because 2 of the 8 coins are dimes. Is he correct? Explain
Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

No. Choosing two dimes are dependent events. The probability of choosing the first dime is 1/4 and the probability of choosing the second dime is 1/7 . The probability that both coins are dimes is

Step-by-step explanation:

Crank3 years ago
4 0

Answer:

.

Step-by-step explanation:

The events are dependent.

The size of the original sample space is 8. It changes to 7 after the first dime is chosen.

The probability of picking the first dime is 2/8.

The probability of picking the second dime is 1/7

To find the probability of the compound event, multiply the probabilities.

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3 years ago
What are the exact solutions of x2 = 5x + 2? (1 point)
bazaltina [42]

Answer:

A. x equals 5 plus or minus the square root of thirty-three all over 2

Step-by-step explanation:

Let's move all the terms to one side:

x^2=5x+2

x^2-5x-2=0

Now, we want to use the quadratic formula, which states that for a quadratic equation of the form ax^2+bx+c=0, the roots can be found with the equation: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 1, b = -5, and c = -2, so plug these in:

x=\frac{-(-5)+\sqrt{(-5)^2-4(1)(-2)} }{2(1)}=x=\frac{5+\sqrt{25+8} }{2}=\frac{5+\sqrt{33} }{2}

OR

x=\frac{-(-5)-\sqrt{(-5)^2-4(1)(-2)} }{2(1)}=x=\frac{5-\sqrt{25+8} }{2}=\frac{5-\sqrt{33} }{2}

Thus, the answer is A.

Hope this helps!

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4 years ago
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Answer:

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Step-by-step explanation:

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