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Andreas93 [3]
3 years ago
6

What is the gcf of 16 and 25

Mathematics
2 answers:
dangina [55]3 years ago
6 0
1 is the gcf hope this helps
Salsk061 [2.6K]3 years ago
4 0
The GCF is 1. There is no other number that those numbers have in common.

Hope this helps!!
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!!!KHAN ACADEMY!!! help please
barxatty [35]
Use photomath lollllll
3 0
2 years ago
What is the result when −2/3 subtracted from −14/15?
disa [49]

Step-by-step explanation:

14/15 - 2/3 =

14/15 and 2/3 lcm is 15

so 14/15 becomes 14/15

- 2/3 become 10/15

15÷5=3 and 10÷5=2

so 14/15

-10/15=4/15

14-10 = 4

answer is 4/15 and since 15 can't be divided by 4 equally it is in simplest form at 4/15

7 0
2 years ago
AC =<br> Round your answer to the nearest hundredth.
garri49 [273]

Answer:

the answer is 8.24 using tan =opp/adj

5 0
3 years ago
X=-12-6y <br>-4x+5y=-39<br>slove by the system of substitution
Artist 52 [7]
X = -6y - 12
4x + 5y =-39

                  4x + 5y = -39
     -4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
       24y + 48 + 5y = -39
               29y + 48 = -39
                       29y = -87
                            y = -3

x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6

(x, y) = (6, -3)
5 0
3 years ago
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
3 years ago
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