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ivolga24 [154]
2 years ago
8

PLEASE HELPPP MEEEEEEEEEEE I DK THIS-

Mathematics
1 answer:
Julli [10]2 years ago
8 0

Answer:

FOr the first one you can do:

y= -x +4

y= -x+2

y = -x

y= -x-2

y = x-4

Step-by-step explanation:

I'll do the second one in a different answer use these for now.

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the length of a rectangular patio is 8 feet less than twice its width. the area of the patio is 280 square feet. find the dimens
jolli1 [7]

Answer:

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14

Step-by-step explanation:

<u>Explanation</u>:-

Let 'x' be the width

Given data the length of a rectangular patio is 8 feet less than twice its width

2x-8 = length

The area of rectangle = length X width

Given area of rectangle = 280 square feet

x(2x-8) = 280

2(x)(x-4) =280

x(x-4) =140

x^2 -4x -140=0

x^2-14x+10x-140=0

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The width of the rectangle 14

The length of the rectangle 2x-8 = 2(14)-8 = 28 -8 =20

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14

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