Answer:
Therefore there total of 39 children presented in group of people who attended a ball game.
Step-by-step explanation:
Given:
Total people present=52 .
And there are 3 times children as adults
To Find:
No.of Children Present in Group.
Solution:
<em>Consider 'x' be the children and 'y' be Adults presented in group.</em>
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So there are total of 52 people.
Therefore Equation becomes,
x+y=52.
And also there are 3 times children presented in group as adults were.
So
Children=3 times adults
i.e.x=3y
Using in above Equation we get ,
x+y=52
3y+y=52
4y=52
y=52/4
y=13
Hence there are 13 adults presented in group
So ,
No.of Children=x=3y
=3(13)
=39
No.of.Children =39
Answer:
it is called Common Multiples
So 12/15 simplifies to 4/5, and if you multiply both sides by two you have 8/10 so i guess 2 ( and some extra )
The answer to your question is b.
