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Ira Lisetskai [31]
2 years ago
14

Someone please help me!!

Mathematics
2 answers:
kenny6666 [7]2 years ago
6 0

Answer:

answer attached: x = 5√2

Step-by-step explanation:

Aleksandr-060686 [28]2 years ago
5 0

Answer:

Step-by-step explanation:

All of the right triangles are similar. This means ...

  long side / short side = x/2 = 25/x

Multiplying by 2x gives ...

  x² = 25·2

  x = (√25)(√2)

  x = 5√2

_____

<em>Additional comment</em>

The "geometric mean" of 'a' and 'b' is √(ab). With this in mind, you can see that x is the geometric mean of the lengths 2 and 25. This is always true for this right-triangle geometry.

There are two other geometric mean relations in this geometry, having to do with the other possible ratios of sides. In effect, the length of a segment that touches the hypotenuse (longest side) of the triangle is the geometric mean of the two segments of the hypotenuse it touches.

Left side = √(2·27) = 3√6

Bottom side = √(25·27) = 15√3

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Solve each inequality, and then drag the correct solution graph to the inequality.
Nesterboy [21]

The correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

4(9x-18)>3(8x+12)

First, clear the brackets,

36x-72>24x+36

Then, collect like terms

36x-24x>36+72\\12x >108

Now divide both sides by 12

\frac{12x}{12} > \frac{108}{12}

∴ x > 9

For the second inequality

-\frac{1}{3}(12x+6) \geq -2x +14

First, clear the fraction by multiplying both sides by 3

3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)

-1(12x+6) \geq -6x +42

Now, open the bracket

-12x-6 \geq -6x +42

Collect like terms

-6 -42\geq -6x +12x

-48\geq 6x

Divide both sides by 6

\frac{-48}{6} \geq \frac{6x}{6}

-8\geq x

∴ x\leq  -8

For the third inequality,

1.6(x+8)\geq 38.4

First, clear the brackets

1.6x + 12.8\geq 38.4

Collect likes terms

1.6x \geq 38.4-12.8

1.6x \geq 25.6

Divide both sides by 1.6

\frac{1.6x}{1.6}\geq  \frac{25.6}{1.6}

∴ x \geq  16

Let the graphs be A, B and C from left to right

The first graph (A) shows x\leq  -8 and this matches the 2nd inequality

The second graph (B) shows x \geq  16 and this matches the 3rd inequality

The third graph (C) shows x > 9 and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

Learn more here: brainly.com/question/17448505

8 0
2 years ago
Find the amount and the compound interest on 62500 for1*1/2 years at 8% compounded half-yearly
Anettt [7]

principal (p)=62500,Time (T)=1.5 years,Rate (R)=8% Ammount=p (1+R÷100) =62500 × 1.1664 =72900 again, compound interest = p(1+R÷100)-1=62500×0.1664 = 10400

3 0
2 years ago
I PROMISE BRAINLIST... IT'S SIMPLE PLEASEEEE
ser-zykov [4K]

Answer:

11. 3^2 • 3^5 < 3^8

12. 3^3 • 3^3 > 3^5

13. Option C.

Step-by-step explanation:

11. Which of the following expressions is true?

A.  4^3• 4^4 = 412

4^3• 4^4 = 4^7 = 16384  ❌

B. 5^2 • 5^3 > 5^5

5^2 • 5^3 = 5^5 ❌

C. 3^2 • 3^5 < 3^8

3^2 • 35 = 315 ✔️

D. 5^2 • 54 = 58

5^2 • 54 = 1350 ❌

12. Which of the following expressions is true?

A. 8^3 • 8^2 < 8^4

8^3 • 8^2 = 8^5 ❌

B. 4^4 • 4^4 = 4^16

4^4 • 4^4 = 4^8 ❌

C. 2^2 • 2^6 < 2^8

2^2 • 2^6 = 2^8 ❌

D. 3^3 • 3^3 > 3^5

3^3 • 3^3 = 3^6 ✔️

13. Write the value of the expression: 3^4/3^4

3^4/3^4 = 1

The correct answer is C. 1 ✔️

4 0
3 years ago
3 ft Find the outer perimeter of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate it. 4 ft 5 ft
Sedbober [7]

Answer:

perimeter = 19.42 ft

Step-by-step explanation:

perimeter of semi circle = 6π/2 = 9.42

perimeter of cone = 5 + 5 = 10

10 + 9.42 = 19.42 ft

7 0
3 years ago
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A loan of $1200 had $36 in interest. the rate was 6% . what was the length of the loan
levacccp [35]
6 months


Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
4 0
2 years ago
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