Someone please help me!!

Mathematics

2 answers:

kenny6666 [7]2 years ago

6 0

Answer:

answer attached: x = 5√2

Step-by-step explanation:

Aleksandr-060686 [28]2 years ago

5 0

Answer:

Step-by-step explanation:

All of the right triangles are similar. This means ...

long side / short side = x/2 = 25/x

Multiplying by 2x gives ...

x² = 25·2

x = (√25)(√2)

x = 5√2

_____

<em>Additional comment</em>

The "geometric mean" of 'a' and 'b' is √(ab). With this in mind, you can see that x is the geometric mean of the lengths 2 and 25. This is always true for this right-triangle geometry.

There are two other geometric mean relations in this geometry, having to do with the other possible ratios of sides. In effect, the length of a segment that touches the hypotenuse (longest side) of the triangle is the geometric mean of the two segments of the hypotenuse it touches.

Left side = √(2·27) = 3√6

Bottom side = √(25·27) = 15√3

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16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o

Lynna [10]

Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

$E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)$

where $x_1,x_2,...,x_n$ are the values that the variable can take and $p(x_1),p(x_2),...,p(x_n)$ are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

$E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15$

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

$V(x)=E(x^2)-(E(x))^2$