1. For x<3, h(x)=x+2
now x+2 is an increasing line (a practical way to check, h(1)=3, h(2)=4)
the largest value it takes is at 3, not inclusive, so h(3)=5 not inclusive.
Range_1= (-∞, 5)
2. for x> or equal to 3, h(x)=-x+8, which is a decreasing line (check h(4)=4, h(5)=3 )
so this line takes its maximal value at x=3, f(3)=5 and then takes any other value to -∞.
Range_2=(-∞,5]
3. Range(h)=Range1∪Range2=(-∞, 5)∪(-∞,5]=(-∞,5] (B)
18(y-5)^2=x+3
do the algebra to make it into =x form
x=18y^2-180y+447
then you take the form of the focus, you can do the math
(-215/72, 5)
Answer:
7.5
Step-by-step explanation:
Using pythagoras theorem
Sqrt(9^2-5^2)=7.483
Answer:
4.5 minutes per 1 lap.
Step-by-step explanation:
Answer:-5
-8x-2=-16
-16+11=-5
