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2 years ago

Brainliest Given <3

Mathematics

2 answers:

damaskus [11]2 years ago

8 0

Lily has 32 ounces of orange Juice. if this is 10% more than sav, how much orange juice does sav have?

Answer = 0.9x =32 and 0.1x=32

Danie is purchasing a new video game controller. After a discount of $32 the cost of the controller is $32. what was the original cost of the controller?

Answer = 1.1x=32

wolverine [178]2 years ago

4 0

Answer:

The answer is the first one is B

The answer is the second one is C

Step-by-step explanation:

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I need help working this algebra 2 question 3/4 - 5/6R = 7/10

Brilliant_brown [7]

Answer:

R = 3/50

Step-by-step explanation:

If you are trying to solve for a variable,

1. Simplify both sides of the equation:

3/4 - 5/6R = 7/10 will now be (-5/6r) + 3/4 = 7/10

2. Add -3/4 from both sides of the equation:

(-3/4) + 3/4 = 0 and (-3/4) - 7/10 = -1/20.

You will be left with: -5/6r = -1/20.

3. Divide both sides by (-5/6).

(-5/6r) / -5/6 = 1R or just R. (-1/20) / -5/6 = 3/50

You are left with the answer:

R = 3/50

<em>I hope this helps!</em>

4 0

3 years ago

Read 2 more answers

For brainiest:):):):):):)

azamat

Answer:

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5 0

3 years ago

Due today need asap NO LINKS WILL MARK BRAINLIEST

Tema [17]

Answer:

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8 0

3 years ago

Read 2 more answers

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

4 years ago

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic

Artemon [7]

<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

$\sf{\rightarrow{d = kt}}$