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solmaris [256]
3 years ago
5

If you continually experience budget defi- cits, how can you decide which expenses to cut?

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

you need to cut variable expenses first

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Simplify: (6)(93). Write your answer using an exponent.
strojnjashka [21]

Answer:

toooook teaehes

Step-by-step explanation:

sedmee endm the worlds nssssssssssssss

8 0
3 years ago
Can someone help 10 points
ser-zykov [4K]

Answer:

The volume of this rectangular prism is 72 cubic units. We multiply 6*4*3 to get 72.

7 0
3 years ago
Question is in the picture, please help me out!!
Grace [21]

The arithmetic sequences are as follow:

<h3>What is Arithmetic Sequence?</h3>

An arithmetic sequence in algebra is a sequence of numbers where the difference between every two consecutive terms is the same.

1) t(n) = 5n + 4

t(1) = 9, t(2) = 14, t(3) = 19

So,

9,14,19,...

d= 14-9 = 5

d= 19-14 =5

Hence, it is an AP

2) 1, 2, 4, 8 , 16

Hence, it is not an AP

3) 3, 6, 9 ,...

It is an AP

4)It is given that it is an AP

5) tn =  2*3^n

 t1= 6, t2= 18, t3= 54

So, 6, 18, 54,...

Hence, it is not an AP

6) 3 , 1, 1/3,...

It is not an AP

7) t(n+1)= 6*t(n)

t(1) = -1

t(2)=-6

t(3)= -36

Hence, it is not an AP

8) -3, 1, 5, 9

Hence, it is an AP.

9) 1, 4, 9,...

Hence, it not an AP

10) 2,1,0,1,2,...

It is not an AP

11) t(n)= -2n-5

t(1)= -7, t(2)= -9, t(3)= -11

Hence, it is an AP

12) tn= (1/2)^n

 t1= 1/2, t2= 1/4, t3= 1/8

It is not an AP

Learn more about AP here:

brainly.com/question/24873057

#SPJ1

6 0
2 years ago
Okay that it 5^4x-13=125
Novosadov [1.4K]

Answer:

x=86250

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (1/5)^4*x-13-(125)=0

Step by step solution :

STEP

1

:

           1

Simplify   —

           5

Equation at the end of step

1

:

    1                    

 (((—)4) • x) -  13) -  125  = 0

    5                    

STEP

2

:

Equation at the end of step

2

:

    1                

 ((—— • x) -  13) -  125  = 0

   54                

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  625  as the denominator :

         13     13 • 625

   13 =  ——  =  ————————

         1        625  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x - (13 • 625)     x - 8125

——————————————  =  ————————

     625             625  

Equation at the end of step

3

:

 (x - 8125)    

 —————————— -  125  = 0

    625        

STEP

4

:

Rewriting the whole as an Equivalent Fraction :

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  625  as the denominator :

          125     125 • 625

   125 =  ———  =  —————————

           1         625  

Adding fractions that have a common denominator :

4.2       Adding up the two equivalent fractions

(x-8125) - (125 • 625)     x - 86250

——————————————————————  =  —————————

         625                  625  

Equation at the end of step

4

:

 x - 86250

 —————————  = 0

    625  

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 x-86250

 ——————— • 625 = 0 • 625

   625  

Now, on the left hand side, the  625  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  x-86250  = 0

Solving a Single Variable Equation:

5.2      Solve  :    x-86250 = 0

Add  86250  to both sides of the equation :

                     x = 86250

One solution was found :

x = 86250

                 

7 0
3 years ago
A researcher planned a study in which a crucial step was offering participants a food reward. It was important that three food r
lbvjy [14]

Answer:

Step-by-step explanation:

Hello!

A pilot study was conducted to test if three food rewards are equally appealing to the participants.

Of 60 participants surveyed:

16 preferred cupcakes (CC)

26 preferred candy bars (CB)

18 preferred dried apricots (DA)

If the three types of food are equally appealing for the participants, you'd expect that their proportions will be equal: P(CC)=P(CB)=P(DA)= 1/3

1.

The objective of this pilot study is to test if the observed frequencies follow a theoretical model/ distribution. To analyze this, you have to apply a Chi Square Goodness to Fit test. X^2=sum \frac{(O_i-E_i)^2}{E_i} ~~X^2_{k-1} Where k= number of categories of the variable.

For this example the statistical hypotheses are:

H₀: P(CC)=P(CB)=P(DA)= 1/3

H₁: At least one of the proportions isn't equal to the others.

2.

To calculate the expected frequencies for each category you have to use the formula: E_i= n* P_i where Pi represents the theoretical proportion for the i category, stated in the null hypothesis.

E_{CC}= n* P(CC)= 60*1/3= 20

E_{CB}= n*P(CB)= 60*1/3= 20

E_{DA}= n* P(DA)= 60* 1/3= 20

3.

The cutoff or critical value indicates the beginning of the rejection region for the hypothesis test. For the Chi-Square tests, the rejection region is always one-tailed to the right, meaning that you'll reject the null hypothesis if the value of the statistic is big. For the goodness to fit test you have k-1 degrees of freedom, so the critical value will be:

Assuming α: 0.05

X^2_{k-1;1-\alpha /2}= X^2_{2;0.975}= 7.378

The rejection region is then X²₂ ≥ 7.378

4.

X^2_{H_0}= \frac{(O_{CC}-E_{CC})^2}{E_{CC}} + \frac{(O_{CB}-E_{CB})^2}{E_{CB}}  + \frac{(O_{DA}-E_{DA})^2}{E_{DA}} = \frac{(16-20)^2}{20} +\frac{(26-20)^2}{20} +\frac{(18-20)^2}{20}=  \frac{14}{5}= 2.8

I hope this helps!

5 0
3 years ago
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