<span>System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1
This is the correct answer because not only is it true but it also follows the property of solving systems of equations with adding the equations. To prove that it is true:
2nd equation in system #2 = 1st equation in system #1 + 2(2nd equation in system #1)
</span>10x − 7y = 18 == 4x − 5y = 2 + 2(<span>3x − y = 8)
10x - 7y = 18 == 4x - 5y = 2 + 6x - 2y = 16
10x = 7y = 18 == 10x - 7y = 18</span>
Answer:
noooooooooooooooo
Step-by-step explanation:
Answer:
Events A and B are dependent
Step-by-step explanation:
If A and B are two events such as A and B are dependent then
P(A∩B) P(A) P(B)
An event A will occur with probability 0.4 that is
An event B will occur with probability 0.6 that is
The probability that both A and B will occur is 0.20 that is P(A∩B) = 0.20
Therefore,
P(A∩B) P(A) P(B)
So,
events A and B are dependent
Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
________________________
<span> A = 1/2* h(b1+b2) ;
in which: A = Area = 16 (given);
h = height = 4 (given);
b1 = length of one of the two bases = 3 (given);
b2 = length of the other of the two bases = ? (what we want to solve for) ;
______________________________________________________
Using the formula: </span>A = 1/2 h(b1+b2) ;
________________________________
Let us plug in our known values:
___________________________
→ 16 = (1/2) * 4*(3 + b2) ; → Solve for "b2".
________________________________
→Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ."
________________________________
So, we can rewrite the equation as:
________________________________
→ 16 = 2*(3 + b2) ; → Solve for "b2".
________________________________
We can divide EACH side of the equation by "2"; to cancel the "2" on the "right-hand side" of the equation:
________________________________
→ 16 / 2 = [2*(3 + b2)] / 2 ; → to get:
___________________________
8 = (3 + b2) ;
_________________
→ Rewrite as: 8 = 3 + b2;
_______________________
Subtract "3" from EACH side of the equation; to isolate "b2" on one side of the equation; and to solve for "b2" :
______________________________
→ 8 - 3 = 3 + b2 - 3 ; → to get:
_____________________
b2 = 5; From the 2 (TWO) answer choices given, this value,
"b2 = 5", corresponds with the following answer choice:
____________________
b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
<span>_________________________________________
As far getting "</span>b2 = 5" from: "b2= [16-6]/2= 5"; (as mentioned in the answer choice), we need simply to approach the problem in a slightly different manner. Let us do so, as follows:
<span>_____________________________________
Start from: </span>A = 1/2 h(b1+b2); and substitute our known (given) values):<span>
________________________
</span>→ 16 = (1/2) *4 (3 + b2) ; → Solve for "b2".
_____________________________
Note that: (½)*4 = 2; so we can substitute "2" for: "(1/2) *4" ;
and rewrite the equation as follows:
_________________________
→ 16 = 2 (3 + b2) ;
____________________
Note: The distributive property of multiplication:
_________________________
a*(b+c) = ab + ac ;
_________
As such: 2*(3 + b2) = (2*3 + 2*b2) = (6 + 2b2).
_________________
So we can substitute: "(6 + 2b2)" in lieu of "[2*(3 + b2)]"; and can rewrite the equation:
______________________
→ <span>16 = 6 + 2(b2) ; Now, we can subtract "6" from EACH side of the equation; to attempt to isolate "b2" on one side of the equation:</span>
<span>________________________________________________
</span>→ 16 - 6 = 6 + 2(b2) - 6 ;
→ Since "6-6 = 0"; the "6 - 6" on the "right-hand side" of the equation cancel.
→ We now have: 16 - 6 = 2*b2 ;
___________
Now divide EACH SIDE of the equation by "2"; to isolate "b2" on one side of the equation; and to solve for "b2":
____________________
→ (16 - 6) / 2 = (2*b2) / 2 ;
→ (16 - 6) / 2 = b2 ;
→ (10) / 2 = b2 = 5.
______________
NOTE: The other answer choice given:
_____________
"<span>16= 1/2* 4(3+b2)= 6+2b2" is incorrect; since it does not solve for "b2".</span>
