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goldfiish [28.3K]
3 years ago
14

100 points

Mathematics
2 answers:
Radda [10]3 years ago
8 0

Answer:

ty g

Step-by-step explanation:

forsale [732]3 years ago
7 0

Answer:

omg yes ty meow

Step-by-step explanation:

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Solve the equation 16=9+x
vitfil [10]

Answer:

x = 7

Step-by-step explanation:

9 get subtracted on both sides and then 16-9 is 7

5 0
3 years ago
Read 2 more answers
The histogram below shows information about the number of hamburgers students ate in a month:
Travka [436]
The given histogram represents <span>the number of hamburgers students ate in a month :
</span>
From the histogram we can conclude the following:
(1) 8 students ate (0 - 4) hamburgers 
(2) 3 students ate (5 - 9) <span>hamburgers </span>
(3) 2 students ate (10 - 14) <span>hamburgers
</span>
note: we don't know how many students ate exactly 5 hamburgers.

<span>So, the answer
</span>
The information which is provided in the histogram<span>
</span><span>
</span><span>The number of students who ate 10 hamburgers or more </span>



7 0
3 years ago
Read 2 more answers
Twellve concert tickets cost $450 what is the cost of 3 tickets to the same concert
Scrat [10]
1) $450/12=$37.50
2)$37.50x3=$112.50

The answer is: $112.50

I hope this helps
4 0
4 years ago
Professor Burger orders flowers to be delivered to his mother. The flowers cost $59.95, not including tax. A bouquet of flowers
creativ13 [48]

Answer:$60.30

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
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