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Ivan
3 years ago
5

Equivalent fraction for 1/4

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

There are an infinite number of them.
Here are a few:

2/8,   3/12,   6/24,   10/40,   22/88,   9/36,  

31/124,   123/492,   500/2000,   198/792 
________________________________________

Here's how you can make as many of them as you want:

-- Pick any number.  Write it on top of a new fraction.

-- Multiply your number by  4.  Write the product
on the bottom of the new fraction.

Now your new fraction is equivalent to  1/4 .

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valentina_108 [34]

Answer:

x<-2.5 =(2x+5)-(2x-5) 2. 5-5

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Step-by-step explanation:

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3 years ago
Find two positive numbers whose product is 36 and whose sum is a minimum.
alukav5142 [94]
Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
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3 years ago
Find the missing angles for each problem, given that lines a and b are parallel (step by step)
marshall27 [118]

Answer:

1) 40°

2) 140°

3) 140°

5)40°

6)140°

7)140°

8)40°

Step-by-step explanation:

1 = 40 °        <em>  [Vertically Opposite angles are equal]</em>

8 = 40 °         <em>[Corresponding Angles are equal]</em>

5 = 8 = 40°  <em> [Corresponding Angles are equal]</em>

7 = 180° - 40° = 140°      <em>[Supplementary angles sum 180°]</em>

6 = 140°           <em> [Vertically Opposite angles are equal]</em>

2 = 140°            <em>[Corresponding Angles are equal]</em>

3 = 140 °          <em> [Vertically Opposite angles are equal]</em>

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3 years ago
10 chefs can prepare a meal for 536 people in
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8 0
3 years ago
Read 2 more answers
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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