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stellarik [79]
4 years ago
5

The SI units of mass density are kg/m3, but there are several other common units. One of the most commonly used units of mass de

nsity is gram per cubic centimeter, or g/cc. This is because pure water has a mass density of 1 g/cc. It turns out that 1 mL of liquid is equal to 1 cc of volume. So it is also possible to express the mass density of water as 1 g/mL. This makes water a useful tool since it is possible to use graduated cylinders to measure volumes. An object with a mass of 59.0 g displaces 827.5 ml of water when it is completely immersed. What is the buoyant force on the mass?
Physics
1 answer:
gulaghasi [49]4 years ago
3 0

Answer:

Explanation:

Given

mass of object m=59\ gm

Volume displaced V_d=827.5\ ml

According to Archimedes' principle buoyant force equals to weight of volume displace by an object.

Therefore Buoyant force F_b=\rho \times V_d\times g

where \rho =Density\ of\ water(1000\ kg/m^3)

g=acceleration due to gravity

substituting values

F_b=1000\times 0.8275\times 10^{-3}\times 9.8

F_b=8.109\ N                                                                    

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If they're both dropped at exactly the same time, then the melon at 32m hits the ground first.

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3 years ago
Does bouncing or sticking produce more impulse?
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Answer:

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4 0
3 years ago
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Rufina [12.5K]

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This is also known as length contraction theory

As we know here that

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so here we know that

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8 0
3 years ago
One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren
katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

\sigma = \frac{F}{A}

Where,

\sigma =Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

\sigma_y = \frac{F_y}{A}

where,

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311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}

Resolving for F,

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PART B) We need here to apply the shear strength equation, then

\sigma_y = \frac{F_y}{A}

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3 years ago
What is the net force?(please don't forget the direction and magnitude)​
elena55 [62]

Answer: In mechanics, the net force is the vector sum of forces acting on a particle or object. The net force is a single force that replaces the effect of the original forces on the particle's motion.

Explanation: Hope dis helps u

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