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Nadusha1986 [10]
2 years ago
8

What are the values of rand s?​

Mathematics
1 answer:
Vitek1552 [10]2 years ago
7 0

Answer:

s=15

r=10

Step-by-step explanation:

What we know)

The measure of a line is 180º

If two parrel lines are cut by a transversal, the corresponding angles are congruent (corresponding angles postulate)

What we can figure out)

The angle measuring 3r+3s and 6r+3s are on the same line, so

3r+3s+6r+3s=180

3r+3s and 6r+s are corresponding, so

3r+3s=6r+s

Solve)

Now, we just need to solve the equations.

3r+3s+6r+3s=180 can be condensed into 9r+6s=180 by combining like terms. Then, you can divide by 3 to get 3r+2s=60

3r+3s=6r+s can be turned into 2s=3r by subtracting 3r and s.

So we have 3r+2s=60 and 2s=3r

We can substitute 2s for 3r

2s+2s=60

4s=60

s=15

Then, we can plug s=15 into the equation

2(15)=3r

30=3r

r=10

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Step-by-step explanation:

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2 years ago
The line y =3x-5 meet x-axis at the point M.
dusya [7]

y = 3x - 5 meets the x-axis at the x-intercept, and that happens when y = 0


\bf \stackrel{y}{0}=3x-5\implies 5=3x\implies \cfrac{5}{3}=x~\hspace{5em}\stackrel{M}{\left( \frac{5}{3},0 \right)}


3y + 2x = 2, meets the y-axis when x = 0, and that'd be the y-intercept


\bf 3y+2(\stackrel{x}{0})=2\implies 3y=2\implies y=\cfrac{2}{3}~\hspace{5em}\stackrel{N}{\left( 0,\frac{2}{3} \right)}


so let's find the equation of the line with points M and N in standard form, bearing in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

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• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


\bf M(\stackrel{x_1}{\frac{5}{3}}~,~\stackrel{y_1}{0})\qquad N(\stackrel{x_2}{0}~,~\stackrel{y_2}{\frac{2}{3}}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{~~\frac{2}{3}-0~~}{0-\frac{5}{3}}\implies \cfrac{2}{3}\cdot -\cfrac{3}{5}\implies -\cfrac{2}{5}


\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=-\cfrac{2}{5}\left( x-\cfrac{5}{3} \right)\implies y=-\cfrac{2}{5}x+\cfrac{2}{3} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15y=-6x+10}\implies \stackrel{\textit{standard form}}{6x+15y=10}\implies 6x+15y-10=0

3 0
3 years ago
Question 5
sergey [27]

Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 * 5 = 330. At the same time 22 * 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.

We can also tell that 15, 22 fit into 330 through another approach. 22 * 3 = 66, and 66 * 5 = 330, so 5 * 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.

3 0
3 years ago
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<img src="https://tex.z-dn.net/?f=if%20x%20%3D%20-5%5C%5Cx%5E%7B2%7D%20%2B%203%5C%5Cx%20-%202" id="TexFormula1" title="if x = -5
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Answer:

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8 0
3 years ago
When I want to find the maximum or minimum height of an object I should​
Vedmedyk [2.9K]

Answer:

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Step-by-step explanation:

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