Answer:
24
Step-by-step explanation:
f(n) = f(n − 1) + 3
if n = 7 => f(7) = f(7-1) + 3 = f(6) + 3
if n = 6 => f(6) = f(6-1) + 3 = f(5) + 3
if n = 5 => f(5) = f(5-1) + 3 = f(4) + 3
if n = 4 => f(4) = f(4-1) + 3 = f(3) + 3
if n = 3 => f(3) = f(3-1) + 3 = f(2) + 3
if n = 2 => f(2) = f(2-1) + 3 = f(1) + 3
if f(1) = 6 then f(2) = 9
f(3) = 12
f(4) = 15
f(5) = 18
f(6) = 21
f(7) = 24
Hello there!
2(x - 3) = 2x + 5
Let's start by using the distributive property for the left side.
(2)(x) + (2)(-3) = 2x + 5
2x - 6 = 2x + 5
Then we need to add 6 to both sides
2x - 6 + 6 = 2x + 5 + 6
2x = 2x + 11
We need to transfer 2x on the left side, we gonna do that by subtracting 2x from both sides
2x - 2x = 2x + 11 - 2x
0 = 11
Thus,
There are no solutions.
I hope this helps!
Good luck with your career!
Use substitution.
2p + 3(2p) = 680
2p + 6p = 680
8p = 680
p = 85
Plug in.
x = 2p
x = 2(85)
x = 170
p = 85
Answer:
40 rubber bands are needed
5 rubber bands will be left from 5 bags of of rubber band
Step-by-step explanation:
Each student will need five rubber bands.
There are eight students
Total rubber bands needed = rubber bands per student × number of students
= 5 × 8
= 40
Total rubber bands needed = 40
Rubber bands come in bags of nine.
Number of bags needed = Total rubber bands needed / number of rubber bands in each bag
= 40 / 9
= 4.44 bags
It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5
5 rubber bands bags will be bought which = 5 × 9
= 45 rubber bands
Only 40 rubber bands are needed
Left over rubber bands = 45 - 40
= 5 rubber bands
Midpoint of (a,b,c) and (e,f,g) is
((a+e)/2,(b+f)/2,(c+g)/2)
just average them
the x value
(2+-2)/2=0/2=0
the y value
(-2+0)/2=-2/2=-1
the z value
(4+6)/2=10/2=5
(0,-1,5) is da midopint