All categories

3 years ago

Solve and check the equation 2(4-5x) = 2(3x+2)

2 answers:

5 0

2(4-5x)=2(3x+2)
8-10x=6x+4
Subtract 4 on both sides
4-10x=6x
Add 10x to both sides
4=16x
Divide both sides by 16
0.25=X

Check

2(4-5x)=2(3x+2)
2(4-5(0.25))=2(3(0.25)+2)
2(4-1.25)=2(0.75+2)
2(2.75)=2(2.75)
5.50=5.50

Tasya [4]3 years ago

3 0

ANSWER: 0,25
Ok done. Thank to me :>

You might be interested in

In Mr. Henry’s class, there are 8 students that wear glasses, and 3 of them are boys. c. Write a ratio that compares the number

Ad libitum [116K]

Answer:

3 : 5

Step-by-step explanation:

Since there are 3 boys, the number of girls is 5.

Causing the ratio to be 3 : 5

5 0

3 years ago

What is the pattern as the exponents decrease?

Nana76 [90]

Can we see the patern please

4 0

3 years ago

What is the surface area of the cone? Express your answer in terms of π.b

weeeeeb [17]

Given:

Radius of the cone = 5 ft

Slant height of the cone = 21 ft

To find:

The surface area of the cone

Solution:

Surface area of cone formula:

$SA=\pi r^{2}+\pi r l$

where r is the radius and l is the slant height.

$SA=\pi \times 5^{2}+\pi \times 5 \times 21$

$SA=\pi \times 25+\pi \times 105$

$SA=25 \pi+ 105 \pi$

$SA=130 \pi$

The surface area of the cone is 130π square feet.

8 0

3 years ago

Please help me<br> solve (x+3) (x+7)

vodka [1.7K]

Step-by-step explanation:

Here, we'll need to multiply these two values together. I'll use the expansion formula, which goes as follows:

$(a+b)(c+d)$

Expand

$ac + ad + bc + bd$

Lets apply this to the following equation:

$(x+3) (x+7)$

Expand.

$(x*x) + (x * 7) + (3 * x) + (3 * 7)$

Simplify.

$(x^2) + (7x) + (3x) + (21)$

Remove parenthesis and add.

$x^2+10x+21$

Answer:

x^2+10x+21

5 0

3 years ago

How do i factor 2x^2+11x+5

ira [324]

For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.

jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.

Now replace bx with jx and kx...

2x^2+x+10x+5 now factor 1st and 2nd pair of terms.

x(2x+1)+5(2x+1)

(x+5)(2x+1)

7 0

3 years ago

Read 2 more answers