L(t)=9-0.5t
t=time in hours,
L(t)=length of candle at time t
(A) substitute t=1,2,3,4,5,6 respectively to get
(1,8.5)
(2,8)
(3,7.5)
(4,7)
(5,6.5)
(6,6)
(B) it is a function because none of the x-values duplicate, (nor the y-values).
(C) If the rate changes to 0.45 "/hr, the relation is still linear.
All linear function with finite slope are functions.
Divide the time he traveled by the distance to find how fast he travels 1 mile, then multiply that by 5 miles:
12 minutes / 2 miles = 6 minutes per mile.
6 minutes per mile x 5 miles = 30 total minutes.
Answer:
BD = 35
Step-by-step explanation:
Calculate CD in right triangle ABC, then BD in right triangle BCD
Using Pythagoras' identity in both triangles.
The square on the hypotenuse is equal to the sum of the squares on the other two sides.
In Δ ADC
CD² + AD² = AC² , substitute values
CD² + 9² = 15²
CD² + 81 = 225 ( subtract 81 from both sides )
CD = 144 ( take the square root of both sides )
CD =
= 12
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In Δ BCD
BD² + CD² = BC² , substitute values
BD² + 12² = 37²
BD² + 144 = 1369 ( subtract 144 from both sides )
BD² = 1225 ( take the square root of both sides )
BD =
= 35