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2 years ago

10

A car rental company charges $56 per day plus $0.30 per mile driven. John paid $86 after renting a car for one day. What equatio

n should he use to find x, the number of miles he drove?

2 answers:

Readme [11.4K]2 years ago

8 0

Answer:

x + 56 = 86

Step-by-step explanation:

Masteriza [31]2 years ago

6 0

Answer:

x + 56 = 86.

Step-by-step explanation:

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Find the average montly loss of a conpany with a loss of 36,000 for one year. What's the equation?

algol13

36,00÷ 12= 3,000 so that would be the average monthly loss.

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Ellis is painting wooden fenceposts before putting them in his yard. They are each 5 feet tall and have a diameter of 1 foot. Th

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Answer:

39.25 cubic feet of paint will be needed by Ellis.

Step-by-step explanation:

Volume of a cylinder:

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2h = 3.14r^2h$

How much paint will Ellis need to paint all the surfaces of the 10 fenceposts?

This is the combined volume of these 10 fenceposts.

They are each 5 feet tall and have a diameter of 1 foot.

Radius is half the diameter, so $r = \frac{1}{2} = 0.5$ . Also $h = 5$

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39.25 cubic feet of paint will be needed by Ellis.

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2 years ago

Solve for the variable in 6/18=x/36

alexdok [17]

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2 years ago

Read 2 more answers

Please help me out please

Ksivusya [100]

By comparing the perimeters, we can deduce the scaling factor:

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2 years ago

the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me

Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c) i) 3

ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey. At the start of the 50 seconds the speed is k metres per second. The distance travelled during the 50 seconds is 1.35 kilometres.

(a) Work out the average speed of the vehicle during the 50 seconds

(b) Work out the value of k.

(c) (i) Calculate the gradient of the graph in the final 10 seconds of the journey

(ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

$Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s$

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

$Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/s$ c) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

$Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40} \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3$

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

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3 years ago