Answer:
17m
(Anyone can correct me if I'm wrong)
Step-by-step explanation:
The following equation would be used: 
We would simply substitute the given values, move the values around then we would get our answer:
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
Answer:
Step-by-step explanation:
Given
On first day bag contained 1 kernels
on second bag contained 2 kernels of corn
on third day bag contained 4 kernels of corn
on n th day bag contains 
kernels of corn
thus on 26 th day bag contains 
kernel
Each kernel weigh 0.07 gm
Therefore kernels weighs 
Therefore on 26 th day kernel weighs 23,488.1024 kg
Answer:
Step-by-step explanation:
3.9
