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vova2212 [387]
2 years ago
13

How do I do this question?

Mathematics
1 answer:
Marat540 [252]2 years ago
4 0

Answer:

x = (y +2)/3

Step-by-step explanation:

y= 3x-2

y+2=3x

x=(y +2)/3

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(7,-4);
olga_2 [115]

Literally just plug it in

6(7) + 5(-4) - 42 = 0

42 -20 -42 = 0

-20 = 0

Not a solution.

8 0
2 years ago
Hey Ummm, so I just wanted to say...............................
Whitepunk [10]

Answer:

4

Step-by-step explanation:

two in two places gives four

8 0
2 years ago
How do you do this question?
vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0
3 years ago
21.) A rectangle has an area of 36 square units. As the length and width change, what do you know about their
natima [27]

Answer:

the length and the width are inversely proportional to each other (l=\frac{36}{w} or w=\frac{36}{l})

Step-by-step explanation:

Let

l units = length of the rectangle,

w units = width of the rectangle.

The area of the rectangle is

\text{Area}=\text{Length}\cdot \text{Width}

A rectangle has an area of 36 square units, so

l\cdot w=36

Complete the table with some values of l and w that fit the previous formula:

\begin{array}{ccc}\text{Length}&\text{Width}&\text{Area}\\ \\36&1&36\cdot 1=36\ un^2.\\18&2&18\cdot 2=36 \ un^2.\\12&3&12\cdot 3=36\ un^2.\\ 9&4&9\cdot 4=36\ un^2.\\l&w&l\cdot w=36 \ un^2.\end{array}

As you can see, the length and the width are inversely proportional to each other (l=\frac{36}{w} or w=\frac{36}{l})

4 0
3 years ago
How to determine a midpoint for a frequency table?
Semmy [17]
The class midpoint is the lower class limit plus the upper class limit divided by 2 . Add the midpoints column to the original table.
3 0
3 years ago
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