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1 year ago

1 Use f(x) = ½ x and ƒ˜¹(x) = 2x to solve the problems. f(2)= f¹1)=[ f(f(2)) =

Mathematics

1 answer:

liq [111]1 year ago

7 0

Answer:

f(2) = 1

(1) = 2

(f(2)) = 2

Step-by-step explanation:

f(x) = x

(x) = 2x

f(2) = (2)

f(2) = 1

(1) = 2(1)

(1) = 2

(f(2)) = 2((2))

(f(2)) = 2(1)

(f(2)) = 2

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The length of a box is four inches less than triple its width in inches. What is the length of the box, in inches, if the box is

Alexeev081 [22]

Answer:

A) 14

Step-by-step explanation:

Take the width: 6 and multiply it 3 times because it says triple.

That gives you: 6 * 3 = 18

Then subtract 4 because it says four inches less than.

That gives you: 18 - 4 = 14

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3 years ago

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a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is

irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer

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2 years ago

Five times my age 4 years ago is the same as 3 times my age in 2 years." How old is Elmo now?

zheka24 [161]

Answer:

elmo is 3 right now

Step-by-step explanation:

5x -4 = 3x+2

2x= 6

x= 3

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2 years ago

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Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

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2 years ago

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lidiya [134]

B is 2,2 A is -1,1 c is 2,-1

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3 years ago

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