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2 years ago

Determine if the following triangles are congruent by SSS or SAS.

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

6 0

Answer:

They are congruent by SAS (Side Angle SIde) test or congruence criterion

Since,

In triangle ABD and triangle BCD

AB = BC (Given)

BD = DB(Common Side)

Angle ABD = Angle CBD

Therefore triangle ABD and triangle BCD by SAS (Side Angle SIde) test or congruence criterion

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Emily is entering a bicycle race for charity. Her mother pledges $0.10 for every 0.25 mile she bikes. If Emily bikes 8 miles, ho

Arlecino [84]

Answer:

0.10 for 1/4 of a mile so 8 would be 32 times more. Which would be .1 x 32 or $3.20

Step-by-step explanation:

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2 years ago

Students did push-ups for a fitness test. Their goal was 20 push-ups. For each student,

ale4655 [162]

Answer:

1- 80%

2- 210%

3- 65%

4- 105%

Step-by-step explanation:

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2 years ago

Find the compound interest on 50000 for 9 month at 8 %

Ahat [919]

Answer:The answer is 5, 414.52

Step-by-step explanation:

Since number of years isn't imputed, it will be assumed it's for 1 year

Hence using Compound interest formula

A = P( 1 + r/n)^not

Inputting values

A = 5000( 1 + 0.08/9) ^ 9*1

A = 5, 414.52

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7 0

3 years ago

You accept a new job with a starting salary of $47,000. You receive a 4% raise at the start of your second year, a 5.6% raise at

Sunny_sXe [5.5K]

Answer:

1yr 47,000, 2nd yr 48,880, 3rd yr 51,617.28, 4th yr 57,346.7981 or 57,346.80

Step-by-step explanation:

1yr 47,000

2nd yr 47,000 x 4% = 48,880

3rd yr 48,880 x 5.6% = 51,617.28

4th yr 51,617.28 x 11.1% = 57,346.7981 or 57,346.80

4 0

2 years ago

A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect

blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

$\tan \theta = \frac{P}{B}$

$\tan \theta = \frac{10}{50}$

$\tan \theta = \frac{1}{5}$

Again applying

$\tan \theta = \frac{P}{B}$

$\frac{1}{5} = \frac{h}{200}$

h = 40 cm

Hence, height of the image is equal to 40 cm.

6 0

2 years ago