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3 years ago

Determine the following product: 2a(4a^3-3a-1)

Mathematics

1 answer:

dexar [7]3 years ago

6 0

2a(4a^3 - 3a - 1) = 8a^4 - 6a^2 - 2a

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11/15 minus 1/3 in simplified form

Mrac [35]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

$\frac{11}{15} - \frac{1}{3} \\ \frac{11}{15} - \frac{1 \times 5}{3 \times 5} \\ \frac{11}{15} - \frac{5}{15} \\ \frac{6}{15} \\ \frac{6 \div 3}{15 \div 3} \\ \frac{2}{5}$

6 0

3 years ago

Read 2 more answers

A- CE=CD B- CE = CA C- BF=DF D- DF=EF please help!!

Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that $\overleftrightarrow{FG}$ and $\overleftrightarrow{AB}$ are perpendicular.

The two statements if true that guarantee $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ are;

$\overline{CE} = \overline{CD}$

$\overline{DF} = \overline{EF}$

Reasons:

The given diagram is the construction of the line $\mathbf{\overleftrightarrow{FG}}$ perpendicular to line $\mathbf{\overleftrightarrow{AB}}$ .

Required:

The two statements that guarantee that $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ .

Solution:

From the point C arcs E and D are drawn to cross line $\overleftrightarrow{AB}$ , therefore;

$\overline{CE} = \mathbf{\overline{CD}}$ arcs drawn from the same radius.

$\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ , given.

Therefore;

$\overline{DF} = \overline{EF}$ by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0

3 years ago

I really need help with this my deadline is very soon

Harman [31]

Answer:

$(3)\ y = -x$

$(5)\ y = -3x -2$

Step-by-step explanation:

Required

The equation in slope intercept form

Solving (3):

$m = -1$

$(x_1,y_1) =(4,-4)$

The equation in slope intercept form is:

$y = m(x - x_1) + y_1$

This gives:

$y = -1(x - 4) -4$

Expand

$y = -x + 4 -4$

$y = -x$

Solving (5):

$m = -3$

$(x_1,y_1) = (1,-5)$

The equation in slope intercept form is:

$y = m(x - x_1) + y_1$

This gives:

$y = -3(x - 1) - 5$

Expand

$y = -3x + 3 - 5$

$y = -3x -2$

8 0

3 years ago

Least to greatest 1.5, 3.25, 1.66, 2.4

arsen [322]

Answer:

least to greatest

A) 1.5, 1.66, 2.4, 3.25

6 0

3 years ago

If f(x)=x^2+3x+5 what is f(3+h) ?

andriy [413]

F(x)=x^2+3x+5
f(3+h)=(3+h)^2+3(3+h)+5
f(3+h)=9+6h+h^2+9+3h+5
f(3+h)=23+9h+h^2

7 0

3 years ago

Read 2 more answers