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2 years ago

12

Shameka buys a blue garden hose that is 16.5 feet long and a green garden hose that is 14.75 feet long. How many feet of garden

hose does she buy?
Help please?

2 answers:

Naily [24]2 years ago

8 0

Add the two together and you get 31.25

LenaWriter [7]2 years ago

6 0

Answer:

21.25 feet

Step-by-step explanation:

16.5 feet

+14.75

=21.25 feets

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3 years ago

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In a game, you pilot a spaceship and gain a point for every asteroid you

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Step-by-step explanation:

If you already have 94 points you can't get lower than that.

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3 years ago

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determ

Hunter-Best [27]

Answer:

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not.

This means that $n = 100, \pi = \frac{20}{100} = 0.2$

68% confidence level

So $\alpha = 0.32$ , z is the value of Z that has a pvalue of $1 - \frac{0.32}{2} = 0.84$ , so $Z = 0.995$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.16$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.24$

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

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3 years ago

Let X1, X2, and X3 represent the times necessary to perform three successive repair tasks at a service facility. Suppose they ar

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Answer:

The mean of the total repair time is 150 minutes.

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Step-by-step explanation:

To solve this problem, we have to use the properties of the mean and the variance. Our random variable is the sum of 3 normal variables.

In the case, for the mean, we have that the mean of the sum of 3 normal variables is equal to the sum of the mean of the 3 variables:

$y=x_1+x_2+x_3 \\\\E(y)=E(x_1+x_2+x_3)=E(x_1)+E(x_2)+E(x_3)\\\\E(y)=50+60+40=150$

For the variance, we apply the property for the sum of independent variables (the correlation between the variables is 0):

$V(y)=V(x_1)+V(x_2)+V(x_3)\\\\V(y)=s_1^2+s_2^2+s_3^2\\\\V(y)=15^2+20^2+10^2\\\\V(y)=225+400+100\\\\V(y)=725$

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3 years ago

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Dafna1 [17]

Answer:

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3 years ago