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3 years ago

Can someone help me with this question?

Mathematics

1 answer:

sesenic [268]3 years ago

3 0

Answer:

One of the angles in the triangle might be 50.

AND

The length of the third side must be 11cm or smaller.

Step-by-step explanation:

-The triangle might be an equilateral triangle (having all the same sides and angles). False, since the triangle sum theorem states that all angles inside of a triangle must add up to 180, so an equilateral triangle would need to have all three angles at 60 degrees.

-One of the angles in the triangle must be 120 (false; it can be anything above 90, which is not only 120)

-The length of the third side must be 11cm or smaller. (True, Triangle Inequality Theorem)

-One of the angles in the triangle might be 50 (possibly, so very much true)

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Find the rule. *

DiKsa [7]

Answer:

y = x - 7

Step-by-step explanation:

You take each equation and sub in for x and y.

The first equation would look like this:

16 = 2(23) - 30 Then you answer looks like this:

16 = 16 but if you did that for the second set in the column it looks like this:

18 = 2(25) - 30

18 = 50 - 30

18 = 20 which does not equal canceling the first answer.

And the second answer doesn't make sense because if x > y you shouldn't add to x. The same goes for the third answer.

So that leaves only one answer y = x - 7

Hope this helps

Sorry if this answer is long

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Answer:

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Step-by-step explanation:

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3 years ago

THE IMAGE DOWN BELOW MATH PLEASE HELP ME WITH THIS ALEGEBRA IM CRYING YALL

Fittoniya [83]

Answer:

25% increase

Step-by-step explanation:

final value (20) -minus- starting value (16)

-------------------divided by ---------------- times * 100

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3 years ago

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

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3 years ago

Need help finding the value of O. Please help..

Kruka [31]

Answer:

O=30° or O=29°

Step By Step Explanation:

∠α =arcsin( a/c )

= arcsin(4/8)

= arcsin(0.5)

= 0.5 rad = 30° = 29°

I Hope This Helps. I Gave you 2 answers just in case 1 is Wrong. And I Hope you Understand This Calculation, I Used Different Variables and the arcsin thing is something my teacher told my class to use, and I Have no Idea what it means because my teacher never explained what it meant, Sadly.

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3 years ago