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3 years ago

What is the percent of decrease from 83.6 to 0?

Mathematics

2 answers:

liq [111]3 years ago

8 0

Step-by-step explanation:

Amount Saved = Product Price * Discount Percentage / 100

Amount saved = (6 * 83) / 100

Amount saved = € 4.98

Simply put, when you buy an item for € 83 and the discount is 6%, you will pay € 78.02 and save € 4.98.

Percentage calculations - examples

50% of 24156895% of 9637871% of 14889069% of 17140493% of 15217659% of 30892891% of 9658486% of 32934540% of 8022392% of 2197621% of 7906398%

liraira [26]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

una familia ha consumido en un dia de verano: dos botellas de litro y medio de agua, 5 botellas de 1/4 de litro de jjugo de appl

aleksandr82 [10.1K]

Answer:

La familia ha bebido en un día de verano $5\,\frac{1}{4}$ litros.

Step-by-step explanation:

Podemos evidenciar que es posible obtener el volumen total de los citados líquidos al sumar el volumen de cada uno. El volumen de cada bebida es igual al producto de su capacidad multiplicada por el número de botellas. Es decir:

$V_{total} = V_{agua} + V_{jugo} + V_{limonada}$

Donde todos los volúmenes se miden en litros.

$V_{total} = (2\,botellas)\times \left(\frac{3}{2} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$

$V_{total} = (2\,botellas)\times \left(\frac{6}{4} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$

$V_{total} = \frac{12}{4}\,L + \frac{5}{4} \,L + \frac{4}{4} \,L$

$V_{total} = \frac{21}{4}\,L$

$V_{total} = \frac{20}{4}\,L + \frac{1}{4}\,L$

$V_{total} = 5\,\frac{1}{4}\,L$

La familia ha bebido en un día de verano $5\,\frac{1}{4}$ litros.

3 0

3 years ago

What two numbers multiply to get -420 and add to get -32

netineya [11]

I'm not at my desk and can't check it out right now.
But I think you should try 10 and -42 .

7 0

4 years ago

Please help!!<br> I need it quick!!!

sladkih [1.3K]

Answer:

-13 $\frac{13}{25}$

Step-by-step explanation:

To multiply fractions with both the fraction and whole number you must convert it to an improper fraction by multiplying the whole numbers by the denominators, which you would get 35 for the first fraction and -10 for the second, then you must add the numerators to that number and put the number into the numerator spot. at this point you should have $\frac{39}{7}$ and $\frac{-12}{5}$ .

Now, multiply the numerators by the numerators and the denominators by the denominator and keep it aligned so the products stay in fraction form. now you should have $\frac{-468}{35}$ .

Divide the numerator by the denominator to get the whole number, in this problem that comes out to 13. The remainder of this division becomes the new numerator which in this case would also be 13 and the denominator stays the same so now you have -13 $\frac{13}{35}$ which is the answer

Hope i helped!

3 0

3 years ago

Read 2 more answers

Factor the polynomial: – x3 - 4x2 - 5x

Alinara [238K]

Answer:

$-x3-4x2-5x=-x(x^2+4x+5)$

Step-by-step explanation:

we are given the polynomial as

$-x3-4x2-5x$

here we can see that the GCF of $-x^3$ , $-4x^2$ and $-5x$ is

$-x$

Hence we take it outside the bracket

$-x(x^2+4x+5)$

The polynomial within the bracket $x^2+4x+5$ can not be factorized further , hence this would be our final answer.

3 0

3 years ago

How many real solutions if any, does 2x^2-3x+8=0

fenix001 [56]

Answer:

The quadratic equation $2\, x^{2} - 3\, x + 8 = 0$ has no real solution.

Step-by-step explanation:

Rewrite the quadratic equation $2\, x^{2} - 3\, x + 8 = 0$ in the standard form $a\, x^{2} + b\, x + c = 0$ :

$2\, x^{2} + (-3)\, x + 8 = 0$ , for which:

$a = 2$ .
$b = (-3)$ .
$c = 8$ .

The quadratic discriminant of $a\, x^{2} + b\, x + c = 0$ is $(b^{2} - 4\, a\, c)$ . The quadratic discriminant of $2\, x^{2} + (-3)\, x + 8 = 0$ would be:

$\begin{aligned}& b^{2} - 4\, a\, c \\ =\; & (-3)^{2} - 4 \times 2 \times 8 \\ =\; & (-55)\end{aligned}$ .

Since the quadratic discriminant of this equation is negative, this quadratic equation has no real solution.

3 0

2 years ago