Question

HELP ME NOW OR I WILL GET SLENDERMAN IN HERE TO GET YALL!!!!!

Answer 1

$\boxed{\sf a_n=-3a_{n-1}+6}$

$\sf\longmapsto a_1=-2$

$\sf\longmapsto a_2=-3a_1+6=-3(-1)+6=3+6=9$

$\sf\longmapsto a_3=-3a_2+6=-3(9)+6=-27+6=-21$

$\sf\longmapsto a_4=-3a_3+6=-3(-21)+6=63+6=69$