Question

A tank with capacity T gallons is empty. If water flows into the tank from pipe X at the rate of X gallons per minute, and water is pumped out by pipe Y at the rate Y gallons per minute, and X is greater than Y, in how many minutes will tank be filled?

Answer 1

A tank with capacity T gallons is empty. Tank will be filled in $\frac{t}{(x - y)}$ minutes

Solution:

Given, A tank with capacity T gallons is empty.  

We have to find how many minutes will tank be filled?

Now, Water flows into the tank from pipe X at the rate of X gallons per minute,  

And water is pumped out by pipe Y at the rate Y gallons per minute,  

Then, together in one minute the amount of water filled will be x – y gallons  [as X is greater than Y]

Now, the time take to fill tank = $=\frac{\text { capacity of tank }}{\text { amount of water filled per minute }}=\frac{t}{x-y}$

Hence tank will be filled in $\frac{t}{(x - y)}$ minutes