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Neporo4naja [7]
4 years ago
13

A tank with capacity T gallons is empty. If water flows into the tank from pipe X at the rate of X gallons per minute, and water

is pumped out by pipe Y at the rate Y gallons per minute, and X is greater than Y, in how many minutes will tank be filled?
Mathematics
1 answer:
Andrej [43]4 years ago
6 0

A tank with capacity T gallons is empty. Tank will be filled in \frac{t}{(x - y)} minutes

<u>Solution:</u>

Given, A tank with capacity T gallons is empty.  

We have to find how many minutes will tank be filled?

Now, Water flows into the tank from pipe X at the rate of X gallons per minute,  

And water is pumped out by pipe Y at the rate Y gallons per minute,  

Then, together in one minute the amount of water filled will be x – y gallons  [as X is greater than Y]

Now, the time take to fill tank = =\frac{\text { capacity of tank }}{\text { amount of water filled per minute }}=\frac{t}{x-y}

Hence tank will be filled in \frac{t}{(x - y)} minutes

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