What is the best estimate for this sum 1/8+1/6=The sum will be close to?
1 answer:
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Try this:
Given:
![\left \{ {{x-y=1} \ [1] \atop {x+y=3} \ [2]} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7Bx-y%3D1%7D%20%5C%20%5B1%5D%20%5Catop%20%7Bx%2By%3D3%7D%20%5C%20%5B2%5D%7D%20%5Cright.%20)
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
Given:
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
Answer:
3.5 cm
Step-by-step explanation:
In the picture attached, circle M is shown.
From the picture, minor arc JH measures 25°.
The length of the circle is π*Diameter = π*16 = 50.26 cm. This length is proportional to 360°. To find the length of minor arc JH, we have to use the next proportion:
50.26 cm / x cm = 360° / 25°
x = 50.26*25/360
x = 3.5 cm
The function has a y-intercept at (0, 2). Then the correct options are A, B, and E.
The complete question is attached below.
<h3>What is the maximum and minimum value of the function?</h3>The condition for the maximum will be
f"(x) < 0
The condition for the minimum will be
f"(x) > 0
Consider the inverse function.
f⁻¹(x) = -√(x - 2)
Then the conclusion of the function f(x) = x² + 2 will be
Differentiate the function, then we have
f ' (x) = 2x
Again differentiate, then we have
f" (x) = 2
f" (x) > 0
Then the function has a minimum value at (0, 2)
The function has a y-intercept at (0, 2)
Then the correct options are A, B, and E.
More about the maximum and minimum value of the function link is given below.
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