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Sergeeva-Olga [200]
2 years ago
12

What is the range of possible sizes for side x?

Mathematics
2 answers:
Murljashka [212]2 years ago
8 0

Answer:

it might be 8-9.5 correct me if i am wrong

Step-by-step explanation:

VARVARA [1.3K]2 years ago
3 0
I believe the answer is 8-10.5
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If you multiply two decimals that are less than 1, can you predict whether the product will be less than or greater than either
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6 0
2 years ago
Seven less than the product of a number n and 1/7 is no more than 98.
mars1129 [50]

Answer:
1/7(n)-7
<u><</u> 98

Step-by-step explanation:

3 0
2 years ago
A school chorus has 90 sixth-grade students and 75 seventh-grade students. The music director wants to make groups of performers
Vera_Pavlovna [14]

Answer:

a) 15 is the largest number of groups that can be made.

b) There would 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

Number of sixth-grade students = 90

Number of seventh-grade students = 75

a) What is the largest number of groups that could be formed?

Since the music director wants to make groups with the same combination of sixth and seventh grade students in each group,

The greatest common factor (GCF) of the number of sixth and seventh grade students would give us the required combination.

Factor of 90 = 2*45 = 2*3*15 = 2*3*3*5

Factor of 75 = 3*25 = 3*5*5

The greatest common factors are 3 and 5

GCF = 3*5 = 15

Therefore, 15 is the largest number of groups that can be made.

b. If that many groups are formed, how many students of each grade level would be in each group?

Sixth grade = 90/15 = 6

Seventh grade = 75/15 = 5

Therefore, there would 6 sixth grade students and 5 seventh grade students in each group.

7 0
3 years ago
Suppose that 10 sophomores, 3 juniors, and 10 seniors are candidates for a prestigious mathematics award of which three will be
faltersainse [42]

Answer:

1771 possible ways

Step-by-step explanation:

In this case, we need to know first how many candidates are in total:

10 + 3 + 10 = 23 candidates in total.

Now, we need to choose 3 of them to receive an award. In this case, we have several scenarios, but as it's an award we can also assume that the order in which the candidates are chosen do not matter, so, the formula to use is the following:

C = m! / n! (m - n)!

Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:

C = 23! / 3! (23 - 3)!

C = 2.59x10^22 / 6(2.43x10^18)

C = 1771

So we have 1771 ways of choose the candidates.

7 0
3 years ago
Plzzzzzzzzzzzzzzz help what is 6+x÷3=13
saveliy_v [14]

Answer:


Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
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