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emmainna [20.7K]
2 years ago
15

Q. If a pair of linear equations is consistent, then the lines will be:​

Mathematics
2 answers:
AlexFokin [52]2 years ago
8 0

Answer:

Step-by-step explanation:

Intersecting

lutik1710 [3]2 years ago
4 0

Answer:

Intersecting or coincident.

Step-by-step explanation:

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Can you solve for b bh=r
Alenkasestr [34]

Answer: b = r/h

Step-by-step explanation:

To solve for b, simply divide both sides of the equation by h to get:

bh/h = r/h

b = r/h

Hope it helps :) and let me know if you want me to elaborate.

8 0
3 years ago
Read 2 more answers
2) Tara is trying to find the nth term of the arithmetic sequence 5,8,11, and 14…. Which expression can Tara use to find the nth
juin [17]

Answer:

Below in bold.

Step-by-step explanation:

Nth term an = a1 + d(n - 1)   where a1 = term 1 and d = common difference.

Here a1 = 5 and d = 8-5 = 3.

So an = 5 + 3(n - 1)

15th term a15

=  5 + 3(15 - 1)

= 5 + 42

= 47.

4 0
3 years ago
For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
3 years ago
Find the population mean or sample mean as indicated. Sample: 19, 15, 6, 11, 24 Compute the sample mean for this data set. Selec
yKpoI14uk [10]

Answer:

\overline{x}=15

Step-by-step explanation:

the mean is given by:

\overline{x} = \dfrac{\sum\limits_{i=1}^n x_i}{n} \quad\text{or}\quad \dfrac{\text{sum of all items}}{\text{number of items}}

In our case this is:

\overline{x} = \dfrac{19+15+6+11+24}{5} \Rightarrow \dfrac{75}{5}\\\\\overline{x} = 15\\\\

side note: the main difference between sample mean and population mean is in the 'context'. However, the method to calculate them is the same.

By context I mean: if this the items are taken from some larger category for example: the ages of a few 'students' from a 'class'. Here 'students' are the sample from a larger set that is 'class'. The mean of the 'few students' will be called sample mean. In contrast, if we take the mean of the ages of the whole class then this is called population mean. (population mean == mean of the whole set)

In our case we aren't told exactly where these numbers come from, is this the whole set or a sample from it, the lack of context allows us to assume that the mean can either be population mean or sample mean. So we can safely use any symbol \mu or \overline{x}.

3 0
3 years ago
Ht) = -16t+32t+ 10.​
KonstantinChe [14]
Answer:
16t + 10

Explanation:
Step 1 - Add like terms

-16t + 32t + 10
16t + 10
5 0
4 years ago
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