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2 years ago

I need help with 10 to 14

Mathematics

1 answer:

Zigmanuir [339]2 years ago

6 0

Answer:

10- It is linear and the constant of proportionality is $6

11- x-intercept(s): (5,0)

y-intercept(s): (0,−2)

12- y-intercept(s): (0,3)

Slope: -2

13- B) 2/3

14- C) 2

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Step-by-step explanation:

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2 years ago

Read 2 more answers

00.6 times 00.99 how much will you get explain correctly

Helga [31]

Multiple the 2 numbers and you should get 0.594

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3 years ago

In the xy-coordinate plane shown, line L passes through point C and has a slope of -2. A dilation of line {with center A and a s

masya89 [10]

Answer:

C' (-4 , 2)

slope of new line = line "L" = -2

Step-by-step explanation:

C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3

C' (x,y)

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8 0

2 years ago

According to the data, the mean quantitative score on a standardized test for female college-bound high school seniors was 500.

Sveta_85 [38]

Answer:

6.68% of the female college-bound high school seniors had scores above 575.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 50

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(scores above 575)

P(x > 575)

$P( x > 575) = P( z > \displaystyle\frac{575 - 500}{50}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 575) = 1 - 0.9332= 0.0668 = 6.68\%$

6.68% of the female college-bound high school seniors had scores above 575.

7 0

3 years ago

assume that the number of production defects is 28 and that 14 of these are classified as major defects, 8 are classified as des

Arlecino [84]

Answer: 5

Step-by-step explanation:

Let A denotes the number of major defects and B denotes the number of design defect.

By considering the given information, we have

$U=28\ ;\ n(A)=14\ ;\ n(B)=8\ \ ;\ n(A^c\cap B^c)=1$

Now, the number of major defects or design defects:

$n(A\cup B)=U-n(A^c\cap B^c)=28-11=17$

Also,

$n(A\cap B)=n(A)+n(B)-n(A\cup B)\\\\\Rightarrow\ n(A\cap B)=14+8-17=5$

Hence, the number of design defects were major=5

6 0

3 years ago