You can substitute what y is into the second equation, so:
3x + 4(2x + 1) = 26
3x + 8x + 4 = 26
11x + 4 = 26
- 4
11x = 22
÷ 11
x = 2
y = (2 × 2) + 1
y = 5 + 1
y = 5
So you get x as 2 and y as 5, I hope this helps!
Answer:

Step-by-step explanation:
Given functions are:

We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,

Also we have to find
(s-t)(x) => we have to subtract function t from function s

Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

Putting x = -3

Hence,

<span>X-Y=4,
X+Y=2
-------------add
2x = 6
x = 3
X - Y =4
3 - Y = 4
Y = 3 - 4
Y = -1
solution (3 , -1)</span>
By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse
So, hypotenuse = 13