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notka56 [123]
3 years ago
9

1-4 Will give brainliest!!!! Pls show work!!

Mathematics
2 answers:
Troyanec [42]3 years ago
5 0
Here you go kind brain

Aloiza [94]3 years ago
3 0
All you have to do is add or subtract the numerators( top#) and reduce
1) 2/4 divided by 2 = 1/2
2) 4/6 dived by 2 = 2/3
3) 11/ 17 ( can’t be reduced)
4) 2/29 ( can’t be reduced)
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How many ways are there for Alice, Bob, Charlie, David and Eve to line up from left to right, such that Charlie is somewhere to
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120 ways

Step-by-step explanation:

Alice, Bob, David, Charlie,   Eve

David, Alice, Bob,  Charlie,   Eve

Alice,David, Bob,  Charlie,   Eve

Charlie,   Eve ,Alice,David, Bob,  

Charlie,   Eve ,Alice, Bob, David,

Charlie,   Eve ,David, Alice, Bob,

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Bob,Alice,Charlie,   Eve ,  David,   and so .

This is a permutation question as the order of placing Charlie to the left of Eve is important.

So the total number of people n= 5 and the possible order is 4 keeping Charlie left of Eve. Eve cannot have the last position to keep Charlie on the left.

Using the formula of nPr = n!/ (n-r)! we get

5! / (5-4)! = 120 ways in which Charlie can be placed to the left of Eve.

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8 0
3 years ago
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