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zhenek [66]
2 years ago
13

Please help I can't understand and my teacher is not explaining properly.

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
7 0

Answer:

B=100

Step-by-step explanation:

The given circle is

Consider the triangle AOB, Using the triangle sum property, we get

AOB+AOB+BOA=180

Substitute ABO=55 and BAO=45 we get

AOB+55+45=180

AOB+100=180

AOB+100-100=180-100

AOB=80

Here AOB and AOC are supplementary angles

The sum of the supplementary angles is 180 degrees.

AOB+AOC=180

Substitute AOB=80 we get

80+AOC=180

80+ AOC-80=180-80

AOC=100

Now consider the Central angle AOC  and intercepted arc AC.

mAOC=mAC

Substitute m AOC=100 and mAC=b we get

100=b

Hence the value of b is 100 degrees.

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3 Write a numerical expression to model the words. Subtract 1 from the product of 4 and 5.​
umka21 [38]

Answer:

Hello!

After reading the question you have provided I have come up with the correct numerical expression:

4x5-1

Step-by-step explanation:

To come up with this solution you need to keep in mind some of the terminoloy being used.

The word "subtract" comes from the action of subtraction

The word "product" comes from the action of multiplication

Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".

So you get the first part being 4x5

Then, you add in the last part of "subract 1" from the "product of 4 and 5":

4x5-1

<em>Remember to keep in mind the rule of "PEMDAS"</em>

You always need to keep the multiplication portion of the equation in front of any subtraction, or addition in any given equation.

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2 years ago
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Step-by-step explanation:

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Which of the following values of m will result in a true statement when substituted into the given equation?
Schach [20]

Answer:

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Law of radicals
andrey2020 [161]

Answer:

1)  \sqrt{x^7}=x^{\frac{7}{2}

2)  \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}=z^\frac{9}{4}

Step-by-step explanation:

1) \sqrt{x^7}

We know that \sqrt{x}=x^{\frac{1}{2}

So, \sqrt{x^7}=x^{\frac{7}{2}

2) \sqrt[3]{y^5}

We know that \sqrt[3]{x}=x^{\frac{1}{3}

So, \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}

We know that \sqrt[5]{x}=x^{\frac{1}{5}

So, \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}

We know that \sqrt[4]{x}=x^{\frac{1}{4}

So, \sqrt[4]{z^{9}}=z^\frac{9}{4}

6 0
3 years ago
Wilfred is feeding his goats. He gives 56% of the bag of feed to the goats in field A and the rest to the goats in field B. If t
krok68 [10]

Answer:

Feeds = 11.76kg

Step-by-step explanation:

Given

Field\ A= 56\%

Field\ B= The\ rest

Bag = 21kg\ feed

Required

Determine how much goats in field A, get.

To do this, we simply multiply the percentage feed received by goats in field A by the actual bags of feeds

i.e.

Feeds = 56\% * 21kg

Convert percentage to decimal

Feeds = 0.56 * 21kg

Feeds = 11.76kg

<em>Hence, goats in field A get 11.76kg of feeds</em>

6 0
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