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2 years ago

PLEASE HELP. ID REALLY APPRECIATE IT. GOOD MORNING/AFTERNOON/NIGHT BTW

Mathematics

1 answer:

WITCHER [35]2 years ago

7 0

Answer:

Step-by-step explanation:

-3+6=3

-2+5=3

-1+4=3

0+3=3

1+2=3

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What is .07 times 1.22

lidiya [134]

.07×1.22 = ?
first take away the decimals in the question, 7×122 =854.
now add the decimals back to the answer, we had 4 decimal places in the questions so add 4 decimal places to 854 = 0.0854

answer= 0.0854

7 0

2 years ago

The slope of the line below is -5 which of the following is the point-slope form of the line (2,-8)

insens350 [35]

The point slope form has the following syntax.

$y - y_1 = m(x - x_1)$
m = slope = -5
$y - y_1 = -5(x - x_1)$
(x,y) = (2,-8)
$x_1 = 2$
$y_1 = -8$
$y - y_1 = -5(x - x_1)$
$y - (-8) = -5(x - 2)$
$y + 8 = -5(x - 2)$ <------Answer

3 0

3 years ago

If f(x)=x^5-1 g(x)=5x^2 and h(x)=2x which expression is equivalent to [g*f*h](9)

vagabundo [1.1K]

F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x

Answer:
$\underbrace{5(\underbrace{(\underbrace{2\cdot9}_{h(9)})^5-1}_{f(g(9))})^2}_{g(f(h(9)))}$ $\boxed{C.}$

6 0

2 years ago

20 units Humulin R insulin in 100 mL of normal saline (NS) to infuse for 20 hours. (Round to the nearest tenth if applicable) a.

wariber [46]

Answer:

a) 1 unit per hour will be infused.

b) 5mL per hour will be infused.

Step-by-step explanation:

Each question can be solved as a rule of three with direct measures, that means we have a cross multiplication.

a. How many units per hour will be infused?

20 units are going to be infused in 20 hours. How many units are going to be infused each hour?

1 hour - x units

20 hours - 20 units

$20x = 20$

$x = \frac{20}{20}$

$x = 1$

1 unit per hour will be infused.

b. How many milliliters per hour will be infused?

100mL are going to be infused in 20 hours. How many mL are going to be infused each hour?

1 hour - x mL

20 hours - 100 mL

$20x = 100$

$x = \frac{100}{20}$

$x = 5$

5mL per hour will be infused.

4 0

2 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago