A ball is thrown from an initial height of 3 feet with an initial upward velocity of 37 fts. The ball's height h (in feet) after
1 seconds is given by the following.
h= 3+37t-16t^2
Find all values of t for which the ball's height is 23 feet.
1 answer:
Answer:
t=(37+root89)/32,(37-root89)/32
Step-by-step explanation:
Solve the equation:
23=3+37t-16t^2
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