All categories

2 years ago

Given m = 7 and the point (3, -1), which of the following is the point-slope form of the equation

Mathematics

2 answers:

dalvyx [7]2 years ago

6 0

Answer:

y = 7x - 22

Step-by-step explanation:

We know that point-slope form is y = mx + b (b is y-intercept, m is slope, and the y and x is of any point on the line)

We can plug in m as 7, y as -1, and x as 3 to get:

-1 = 21 + b

You can subtract 21 on both side to get b = -22.

Then, we plug in m = 7 and b = -22 to y = mx+b to get y = 7x + (-22) which simplifies to:

y = 7x - 22

pychu [463]2 years ago

4 0

Hope this helps! Answer is highlighted. If you have any questions you can ask.

You might be interested in

What is the ratio for the surface areas of the rectangular prisms shown below, given that they are similar and that the ratio of

Harrizon [31]

Answer:

9 : 1

Step-by-step explanation:

given a linear ratio = a : b, then the corresponding area ratio is

a² : b²

Here the linear ratio of their edges = 3 : 1, hence

ratio of surface areas = 3² : 1² = 9 : 1

4 0

3 years ago

What are the rise and run of the line whose equation is y=15x?

Blababa [14]

Answer:

Rise = 15.

Run = 1.

Step-by-step explanation:

Hope this helps!

5 0

2 years ago

How many solutions does 4x-1/8=-1/8 (32x-1) have

Tom [10]

It has only one solution

3 0

2 years ago

Sin (3x+15) = Cos (7x-2)<br><br> Find value of x

11Alexandr11 [23.1K]

$\bf \textit{Cofunction Identities}
\\ \quad \\
\boxed{sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})}\qquad 
cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})\\\\
-------------------------------\\\\$

$\bf \begin{array}{lcllclll}
sin(&90^o-\theta)&=&cos(&\theta)\\
&\uparrow &&&\uparrow \\
&3x+15&&&7x-2\\
&\downarrow \\
&90-(7x-2)
\end{array}
\\\\\\
90-(7x-2)=3x+15\implies 90-7x+2=3x+15
\\\\\\
92-15=10x\implies 77=10x\implies \cfrac{77}{10}=x$

5 0

3 years ago

A flagpole casts a shadow 16.60 meters long Tim stands at a distance of 12.45 meters from the base of the flagpole such that the

coldgirl [10]

This problem is solely on right triangles, wherein the Pythagorean theorem may be applied. We must first find the angle of elevation of the flagpole using Tim's height and the difference between the shadow of the flagpole and Tim's distance from the flagpole. Therefore tan a = 1.65/(16.6-12.5) where a=21.68 degrees. We use this angle to determine the height of the flagpole. tan 21.68 = x/ 16.6 where x=height of flagpole=6.6 meters.

6 0

3 years ago