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2 years ago

Given m = 7 and the point (3, -1), which of the following is the point-slope form of the equation

Mathematics

2 answers:

dalvyx [7]2 years ago

6 0

Answer:

y = 7x - 22

Step-by-step explanation:

We know that point-slope form is y = mx + b (b is y-intercept, m is slope, and the y and x is of any point on the line)

We can plug in m as 7, y as -1, and x as 3 to get:

-1 = 21 + b

You can subtract 21 on both side to get b = -22.

Then, we plug in m = 7 and b = -22 to y = mx+b to get y = 7x + (-22) which simplifies to:

y = 7x - 22

pychu [463]2 years ago

4 0

Hope this helps! Answer is highlighted. If you have any questions you can ask.

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the ratio of the number of adults to the number of children in a library is 12:5 if there are 45 children in the library how my

anygoal [31]

I’m guessing 108. 45 divided by 5 is 9, so 9 times 12 is 108.

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2 years ago

Read 2 more answers

Suppose that the rate of return on stocks is normally dis-tributed with mean of 9% and a standard deviation of 3%. If I pick fiv

alisha [4.7K]

Answer:

The probability that at least two stocks will have a return of more than 12% is 0.1810.

Step-by-step explanation:

Let X = rate of return on stocks.

The random variable X follows a Normal distribution, N (9, 3²).

Compute the probability that a stock has rate of return more than 12% as follows:

$P(X\geq 12)=1-P(X$

**Use the z table for the probability.

The probability of a stock having rate of return more than 12% is 0.1587.

Now define a random variable Y as the number of stocks that has rate of return more than 12%.

The sample size of stocks selected is, n = 5.

The random variable Y follows a Binomial distribution.

The probability of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...$

Compute the value of P (X ≥ 2) as follows:

P (X ≥ 2) = 1 - P (X < 2)

= 1 - P (X = 0) - P (X = 1)

$=1-{5\choose 0}(0.1587)^{0}(1-0.1587)^{5-0}-{5\choose 1}(0.1587)^{1}(1-0.1587)^{5-1}\\=1-0.4215-0.3975\\=0.1810$

Thus, the probability that at least two stocks will have a return of more than 12% is 0.1810.

6 0

3 years ago

Of the 30 cars in a parking lot, 12 are blue, 8 are red, 6 are white, and 4 are silver. In simplest form, what are the odds in f

Radda [10]

Answer:

Step-by-step explanation:

8+6=14

14/30 = 7/15

So the final answer is 7/15

pls thank me pls :(

3 0

2 years ago

The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota

Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0

3 years ago

HELP ASAP I give brainliest!

Bingel [31]

1. 5%

2. That’s the only answer I have, sorry.

8 0

2 years ago