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Stolb23 [73]
3 years ago
11

What is 7 fewer than a number s

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

What is 7 fewer than a number s?

Answer: s - 7

Hope that helps...

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Ind the slope and y intercept of -9x+3y=5
Radda [10]

Answer:

first, you need to get y on one side. So, because the x is negative it becomes positive when you switch it to the other side. 3y= 9x+5. You then need to divide all parts by 3. 3/3= 1 so thats just y. 9/3 is 3 so thats 3x. then 5/3 is a fraction that you can write as just 5/3 or 1 and 2/3. That would leave you with y= 3x + 5/3. Then x (3) is your slope. and what you add to it (5/3) is your y int.

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3 years ago
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Sonja [21]

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4 0
3 years ago
If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by div
Dafna1 [17]
Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / <span>8St^2
Rewriting the squared terms in simplified form :
</span>Width = 16 x S x S x t / <span>8 x S x t x t
</span>Cancelling the like terms
Width = 16 x S / <span>8 x t
</span>Cancelling the numeric terms :  

Width = 2S / <span>t</span>
6 0
3 years ago
Use the quadratic formula to determine the exact solutions to the equation.
kozerog [31]
Answer:  " x = 1  + √5 " or " x = 1 − √5" .
______________________________________________________
Given:
______________________________________________________

   " x² − 2x − <span>4 = 0 " ;
______________________________________________

Solve for "x" by using the "quadratic formula" :

</span>Note:  This equation is already written in "quadratic format" ; that is:

  " ax² + bx + c = 0 " ;  { "a \neq 0" } ;

in which:   "a = 1" {the implied coefficient of "1" ;
                         since "1", multiplied by any value, equals that same value};

                 "b = -2 " ;

                 "c = -4 " ;
_______________________________________________________
The quadratic equation formula:

x = { - b ± √(b² − 4 ac) } / 2a ;   {"a\neq0"} ;
______________________________________________________
Substitute our known values:
______________________________________________________

   →  x = { - (-2) ± √[(-2)² − 4(1)(-4)] } / 2(1) ; 

       →  x  = { 2 ± √(4 − 4(-4) } / 2 ; 

       →  x  = { 2 ± √(4 − (-16) } / 2 ;

       →  x  = { 2 ± √(4 + 16) } / 2 ;

       →  x  = { 2 ± √(20) } / 2 ;

       →  x  = { 2 ± √4 √5} / 2 ;

       →  x  = { 2 ± 2√5} / 2 ;

       →  x = 1 ± √5 ; 

_______________________________________________________
→  "x = 1 + √5"  or  "x = 1 − √5" .
_______________________________________________________
8 0
3 years ago
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