Answer: [0,+infiniti)
Step-by-step explanation:
Answer:
1. (4, 12) = Quadrant I
2. (-5, 2) = Quadrant II
3. (-9, -4) = Quadrant III
4. (3, -3) = Quadrant IV
Step-by-step explanation:
When thinking about quadrants, remember these rules:
Quadrant I: The x and y values are positive.
Quadrant II: The x value is negative, the y value is positive.
Quadrant III: The x and y values are negative.
Quadrant IV: The x value is positive, the y value is negative.
Apply this concept to your question and you'll be able to get the answer like I showed above. Remember that coordinates are always in (x, y) form.
Hope this helps.
Answer:
2 i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
First you determine the variables x and y as:
x: the value for student tickets
y: the value for chaperone tickets.
Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:
x= y +2
On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:
59x + 6y = 508
Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:
Solving for x, the price of a student ticket:
Rearranging the first equation,
y = x - 2
Replacing in the second equation and solving for x:
59*x + 6*(x -2)=508
59*x + 6*x -12=508
65*x -12=508
65*x= 508 +12
65*x= 520
x=8
The cost of a student ticket is 8$