<h2>
Answer:</h2><h3>False</h3><h2>
Step-by-step explanation:</h2>
Let's find the inverse function of 
to know whether this function has an inverse function ![f^{-1}(x)=-3+\sqrt[3]{x+4}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D-3%2B%5Csqrt%5B3%5D%7Bx%2B4%7D)
. So let's apply this steps:
a) Use the Horizontal Line Test to decide whether 
has an inverse function.
Given that f(x) is a cubic function there is no any horizontal line that intersects the graph of at more than one point. Thus, the function is one-to-one and has an inverse function.
b) Replace 
by 
in the equation for .
c) Interchange the roles of 
and and solve for
![x=(y-3)^3+4 \\ \\ \therefore x-4=(y-3)^3 \\ \\ \therefore (y-3)^3=x-4 \\ \\ \therefore y-3=\sqrt[3]{x-4} \\ \\ \therefore y=\sqrt[3]{x-4}+3](https://tex.z-dn.net/?f=x%3D%28y-3%29%5E3%2B4%20%5C%5C%20%5C%5C%20%5Ctherefore%20x-4%3D%28y-3%29%5E3%20%5C%5C%20%5C%5C%20%5Ctherefore%20%28y-3%29%5E3%3Dx-4%20%5C%5C%20%5C%5C%20%5Ctherefore%20y-3%3D%5Csqrt%5B3%5D%7Bx-4%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20y%3D%5Csqrt%5B3%5D%7Bx-4%7D%2B3)
d) Replace by 
in the new equation.
![f^{-1}(x)=\sqrt[3]{x-4}+3](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx-4%7D%2B3)
So this is in fact the inverse function and it isn't the same given function. Therefore, the statement is false
Answer:
13 in
Step-by-step explanation:
add them all because its says perimeter
Answer:
∠KJL and ∠KJG
Step-by-step explanation:
Yes it is a linear function
Answer:
One of the other perpendicular bisectors must pass through point B
Step-by-step explanation:
Let's look at the choices:
— incenter equidistant from B and C.
The incenter is on the perpendicular bisector of BC. Every point on that line is equidistant from B and C. This statement is True.
__
— angles B and C are congruent.
As we said above, A (on the perpendicular bisector of BC) is equidistant from B and C. That makes the triangle isosceles. The congruent angles are B and C, opposite congruent sides AC and AB. This statement is True.
__
— the perpendicular bisector of BC passes through the incenter.
The incenter is the point of concurrence of the angle bisectors. Since the perpendicular bisector of BC goes through the a.pex of triangle ABC at A, it is the angle bisector there. Hence the incenter lies on that line. The statement is True.
__
— B lies on one of the other perpendicular bisectors.
This will be true if the triangle is equilateral. Nothing in the problem statement indicates this is the case. The statement is False.
