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3 years ago

Find the highest common factors of 6 and 4

Mathematics

2 answers:

cestrela7 [59]3 years ago

5 0

Answer:

Step-by-step explanation:

factors of 6 = 2*3*1

factors of 4=2*2*1

The highest common factor of 6 and 4 is 2*1=2.

timurjin [86]3 years ago

4 0

Answer:

Step-by-step explanation:

i hope it works and plz give me brainllest

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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

2 years ago

A survey was conducted to determine the amount of time, on average, during a given week SCAD students spend outside of class on

fiasKO [112]

Answer:

Standard Deviation = 5.928

Step-by-step explanation:

a) Data:

Days Hours spent (Mean - Hour)²

1 5 61.356

2 7 34.024

3 11 3.360

4 14 1.362

5 18 26.698

6 22 84.034

6 days 77 hours, 210.834

mean

77/6 = 12.833 and 210.83/6 = 35.139

Therefore, the square root of 35.139 = 5.928

b) The standard deviation of 5.928 shows how the hours students spend outside of class on class work varies from the mean of the total hours they spend outside of class on class work.

5 0

3 years ago

Mind helping me find the rate of change and y intercept???

irga5000 [103]

Answer:

gradient is 8 and y intercept is 0

Step-by-step explanation:

y=mc+b

take one pair of corridants:

8=1m+b

m=8 (change in y values/changes in x values)

8=1x8+b

do the equation

y=0

Have a nice day!!!!!!!!! :-)

5 0

2 years ago

What percent of 8 is 14

seraphim [82]

Answer:

57.14

Step-by-step explanation:

8/14 =x/100

cross multiply

800= 14x

x=57.1428

7 0

3 years ago

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Simplify. 5 - [ - ( - 2)]

Nimfa-mama [501]

Answer:

Step-by-step explanation:

1. A - times a - equals a +, which means [-(-2)] equals (2)

2. 5- (2) equals 5 - 2

3. 5-2= 3

6 0

3 years ago

Read 2 more answers

Find the highest common factors of 6 and 4​

Find the highest common factors of 6 and 4