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scZoUnD [109]
2 years ago
11

Is 9/2 and 4 1/2 equivalent​

Mathematics
2 answers:
Vlada [557]2 years ago
4 0

Answer:

Yes.

Step-by-step explanation:

4 \dfrac 12 = 4+ \dfrac 12 = \dfrac{8+1}2 =  \dfrac 92

Stells [14]2 years ago
3 0

Answer:

Yes, they are equivalent

Step-by-step explanation:

Equivalent fractions are equal in value to each other. The only difference is that 9/2 is an improper fraction while 4 1/2 is a mixed number. In decimal, they both equate to 4.5

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Dmitriy789 [7]

Answer:

its 60

Step-by-step explanation:

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It took Eduardo 8 hours to drive from Buffalo, New York, to New York City, a distance of about 400 miles. Find his average speed
yarga [219]
400 m in 8 hours
200 m in 4 hours
100 m in 2 hours
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3 years ago
A certain brand of dinnerware set comes in three colors: red, white, and blue. Twenty percent of customers order the red set, 45
denis23 [38]

Answer:

a) 0.20

b) 0.45

c) 0.65

d) Yes

e) Yes

f) Z = X + Y (except when X = 1 and Y = 1)

This is because the successes of X and Y are mutually exclusive events but their failures aren't. X and Y cannot both be 1.

Step-by-step explanation:

Probability of a red set = 20% = 0.20

Probability of a white set = 45% = 0.45

Probability of a blue set = 35% = 0.35

Probability of the single set being a red or white set = 20% + 45% = 65% = 0.65

P(X=1) = 0.20, P(X=0) = 1 - 0.2 = 0.80

P(Y=1) = 0.45, P(Y=0) = 1 - 0.45 = 0.55

P(Z=1) = 0.65, P(Z=0) = 1 - 0.65 = 0.35

a) pX = P(X=1) = 0.20

b) pY = P(Y=1) = 0.45

c) pZ = P(Z=1) = 0.65

d) Since only one order is being considered at a time, it isn't possible to order red & white set in a single set, hence, both X and Y cannot both be successes (equal to 1) at the same time. But they can both be failures (both equal to 0) if a blue set is ordered. The successes of X and Y are mutually exclusive events but their failures aren't

e) Is pZ = pX + pY

pX = 0.2, pY = 0.45, pZ = 0.65

Hence, this statement is correct!

f) Z = X + Y

Let's check all the probabilities

when X = 1 and Y = 1, Z = 1

1 ≠ 1 + 1

when X = 0 and Y = 1, Z = 1

1 = 0 + 1

when X = 1 and Y = 0, Z = 1

1 = 1 + 0

when X = 0 and Y = 0, Z = 0

0 = 0 + 0

Hence, Z = X + Y (except when X = 1 and Y = 1)

This is because the success of X and Y are mutually exclusive events but their failures aren't.

8 0
3 years ago
How many complex zeros does the function x^8+3x^2-4
butalik [34]

Answer:

8

Step-by-step explanation:

4 0
3 years ago
How do I get this form?
serg [7]

Short answer: you don't.

The linear term in the numerator of the integral means the form shown is not applicable. Rather, you perform the integration using partial fraction expansion.

\displaystyle\int{\frac{5x+1}{25x^2+60x-13}}\,dx=\int{\frac{5x+1}{(5x-1)(5x+13)}}\,dx\\\\=\frac{1}{35}\int{\frac{5}{5x-1}}\,dx+\frac{6}{35}\int{\frac{5}{5x+13}}\,dx

The integral is ...

... (1/35)ln|5x-1| +(6/35)ln|5x+13| +C

_____

If the numerator of your integral were a constant, then the fractions multiplying the separate partial fraction integrals would have the same magnitude and opposite signs. You would end with the difference of logarithms, which could be expressed as the log of a ratio as shown in your problem statement.

6 0
3 years ago
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