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Advocard [28]
2 years ago
13

Find the median and mode of the following data:

Mathematics
2 answers:
jekas [21]2 years ago
4 0
A is 4 and b is 63 have a good day
kkurt [141]2 years ago
3 0
A) To find the median list the numbers in ascending order. (1, 2, 3, 3, 4, 5, 6, 9, 9) The middle number is the median. So the answer is 4.
The mode is the number that appears the most which is 3 and 9 because they both appear twice.
B) (60, 60, 61, 62, 63, 64, 65, 67, 68) The middle number is 63 so that is the median.
The mode is 60 as it appears the most in the list.
Pls give me the brainliest!
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Which function has a range of all real numbers greater than or equal to -4​
shtirl [24]

Answer:

The domain is all real numbers, and the range is all real numbers f(x) such that f(x) ≤ 4. You can check that the vertex is indeed at (1, 4). Since a quadratic function has two mirror image halves, the line of reflection has to be in the middle of two points with the same y value.

7 0
3 years ago
Find the value of the greater root of x^2 + 10x + 24x = 0 a) -6 b) -4 c) 4 d) 6
Lubov Fominskaja [6]

what formula is applied, I mean what method

3 0
3 years ago
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How many solutions does the system have?<br> y=-2x -4 <br> y=3x + 3
baherus [9]

Answer:

x=−7/5and y=−6/5

Step-by-step explanation:

Step: Substitute−2x−4foryiny=3x+3:

y=3x+3

−2x−4=3x+3

−2x−4+−3x=3x+3+−3x(Add -3x to both sides)

−5x−4=3

−5x−4+4=3+4(Add 4 to both sides)

−5x=7

−5x

−5

=

7

−5

(Divide both sides by -5)

x=−7/5

7 0
3 years ago
There are 31 flavors of ice cream, 2 choices of cones, 1 scoop, 2 scoops, or 3 scoops. How many different choices are there?
Kitty [74]

Answer:

There are 39 different choices

Step-by-step explanation:

Add the the flavors of ice cream the cones and the scoops.

31+2=33

1+2+3=6

33+6=39

Hope this helps

7 0
3 years ago
Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
7 0
3 years ago
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