x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y
Answer:
I think the answer is H
<em>Please consider marking as brainliest!</em>
<em />
<span>3x^2−2x+7=0
</span>3x^2−2x+1/3+7−1/3=<span>0
</span><span>3<span>(x^2−2x/3+1/9)</span>+7−1/3=0
</span><span>3<span><span>(x−1/3)^</span>2</span>+(21−1)/3=0
</span><span>3<span><span>(<span>x−1/3</span>)^</span>2</span>=−<span>20/3
</span></span><span><span>(<span>x−<span>1/3</span></span>)^</span>2</span>=−<span>20/9</span>
Answer:
<h2>
<em>X=</em><em>9</em></h2>
<em>Solution</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
