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weqwewe [10]
3 years ago
5

PLEASE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

is that a test

Step-by-step explanation:

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What is a quartic polynomial function in standard form with zeros -2,4,4,and 3
Travka [436]

We can simply multiply the roots together to find the original function.

(x + 2)(x - 4)(x - 4)(x - 3)

FOIL.

x^2 - 4x + 2x - 8(x - 4)(x - 3)

Combine like terms.

x^2 - 2x - 8(x - 4)(x - 3)

FOIL.

x^3 - 2x^2 - 8x - 4x^2 + 8x + 32(x - 3)

Combine like terms.

x^3 - 6x^2 + 32(x - 3)

FOIL.

x^4 - 6x^3 + 32x - 3x^3 + 18x^2 - 96

Combine like terms.

<h3>x^4 - 9x^3 + 18x^2 + 32x - 96 is the original function with the given roots.</h3>
6 0
3 years ago
Factor the expression by finding the GCF. 16m2 − 12m
ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m  or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

3 0
3 years ago
Read 2 more answers
What is the value of m in the figure below?
Scilla [17]

Answer:

Step-by-step explanation:

6.7

6 0
3 years ago
It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
3 years ago
Evaluate the following expression at x = -4<br> -5x-1
ANTONII [103]
All u have to do is 20-1=19
3 0
3 years ago
Read 2 more answers
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